All categories

3 years ago

Help! JH is a mid-segment of KLM. Find the value of x.

Mathematics

1 answer:

USPshnik [31]3 years ago

7 0

JH = mid-segment of triangle KLM.

ML = 22

(1/2)(ML) = 11

JH = (1/2)(ML) = x

So, x = 11.

You might be interested in

One survey estimates that, on average, the retail value of a mid-sized car decreases by 8% annually. If the retail value of a ca

ivolga24 [154]

Value in 1 year = V*0.92

6 0

3 years ago

The graphs show the distances traveled by two bikers riding at constant rates.

Alik [6]

.......,,,,,....,..,....,.

7 0

3 years ago

What is the value of 24x -60

Aleksandr [31]

Answer:

-1440

Step-by-step explanation:

24x -60 = -1440

3 0

3 years ago

the area of a rectangle is 42.15 square meters. if the length is 21 meters, what is perimeters of the rectangle?

Vsevolod [243]

Answer:

perimeters of the rectangle=p=46.014 metres

Step-by-step explanation:

Given that:

Length (l) = 21 m

Area of rectangle(A) = 42.15 meter-square

Width (w)=?

Required data:

Perimater of Rectangle=p=?

Calculation:

As we know that Area of rectangle=A=l*w

Putting the value we get

42.15 m(square)=(21 m)*w

or w=42.15/21

or w=2.007 m

Now to find perimters of rectangle we know that

p=2(l + w) metres

putting the values

p=2(21+2.007) metres

p=2(23.007) metres

p=46.014 metres

7 0

3 years ago

Read 2 more answers

Allison bought jelly beans to share with her friends. She bought pounds of blueberry jelly beans and pounds of lemon jelly beans

Vaselesa [24]

Answer: $1\dfrac{11}{12}\text{ pounds}$

Step-by-step explanation:

The complete question is provided in the attachment.

Given, Amount blueberry jelly beans= $1\dfrac{1}{4}$ pounds

$=\dfrac{5}{4}$ pounds.

Amount lemon jelly beans = $2\dfrac{1}{3}$ pounds

$=\dfrac{7}{2}$ pounds

Total jelly beans she bought = Amount blueberry jelly beans + Amount lemon jelly beans

$=(\dfrac{5}{4}+\dfrac{7}{3})$ pounds

$=\frac{15+28}{12}\text{ pounds}\\\\=\dfrac{43}{12}\text{ pounds}$

Amount of jelly beans she gave away = $1\dfrac{2}{3}=\dfrac{5}{3}\text{ pounds}$

Amount of jelly beans she has left= Total jelly beans - Amount of jelly beans she gave away

= $\dfrac{43}{12}-\dfrac{5}{3}\\\\=\dfrac{43-20}{12}\\\\=\dfrac{23}{12}\\\\=1\dfrac{11}{12}\text{ pounds}$

She has left $1\dfrac{11}{12}\text{ pounds}$ of jelly beans.

6 0

3 years ago