<u>Given</u>:
Secants S V and T V intersect at point V outside of the circle. Secant S V intersects the circle at point W. Secant T V intersects the circle at point U.
The length of TU is (y - 2).
The length of UV is 8.
The length of SW is (y + 4)
The length of WV is 6.
We need to determine the length of line segment SV.
<u>Value of y:</u>
The value of y can be determined using the intersecting secant theorem.
Applying, the theorem, we get;

Substituting the values, we have;






Thus, the value of y is 6.
<u>Length of SV:</u>
The length of SV is given by




Thus, the length of SV is 16 units.
Hence, Option D is the correct answer.