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Radda [10]
3 years ago
12

HELP MEEEEEEEEEEEEE!!!!!!!!!!!!!!!!

Mathematics
2 answers:
aliina [53]3 years ago
8 0

Answer:

linear or Quadratic

i hope it works

zvonat [6]3 years ago
3 0
Answer: quadratic

you know it’s a quadratic when the second difference is the same number
so

the first difference is:
0 to -3 is -3
-3 to -4 is -1
-4 to -3 is +1
-3 to 0 is + 3

the second difference is:
-3 to -1 is +2
-1 to 1 is +2
1 to 3 is +2

since the second difference is always +2
the function is QUADRATIC
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B is the answer.....
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How do you compare y-intercepts and rates of change
Sphinxa [80]
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3 years ago
Which expression is equal to zero? 9 + (– 27) ÷ (– 3)
GrogVix [38]

Answer:

-27÷(-3)-9

=0

Step-by-step explanation:

Hope this helps you.

4 0
3 years ago
Find the value of y, rounded to the nearest tenth. Please help me, I'd appreciate it!!
Blababa [14]
If a secant<span> and a </span><span>tangent of a circle </span><span>are drawn from a point outside the circle, then the product of the lengths of the secant and its external segment equals the square of the length of the tangent segment.
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y</span>² = 7(15+7)
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8 0
3 years ago
Someone claims that the average amount of time that a freshman at TAMU studies is 7 hours. We think it’s higher than that and de
Stels [109]

Answer:

Test statistic t = 5.25

P-value = 0.000002 (one-tailed test)

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.

Then, the null and alternative hypothesis are:

H_0: \mu=7\\\\H_a:\mu> 7

The significance level is 0.05.

The sample has a size n=49.

The sample mean is M=8.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=√s^2=√4=2.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2}{\sqrt{49}}=0.29

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{8.5-7}{0.29}=\dfrac{1.5}{0.29}=5.25

The degrees of freedom for this sample size are:

df=n-1=49-1=48

This test is a right-tailed test, with 48 degrees of freedom and t=5.25, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t>5.25)=0.000002

As the P-value (0.000002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.

6 0
3 years ago
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