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2 years ago

Given the function f(3) = 36 complete the following table

Mathematics

1 answer:

frozen [14]2 years ago

6 0

Okay so here we have the function f(x)=3x-6 if you plug in -2 to x you get -12 if you plug in -1 you get -9 and if you plug in 0 you get -6 add three each time

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Pls help on my homework. due tonight

aleksklad [387]

Answer:

A line that a curve approaches as it heads towards infinity

The asymptote is -2 there is no end behavior

Step-by-step explanation:

3 0

2 years ago

How is this solved using trig identities (sum/difference)?

GenaCL600 [577]

FIRST PART
We need to find sin α, cos α, and cos β, tan β
α and β is located on third quadrant, sin α, cos α, and sin β, cos β are negative

Determine ratio of ∠α
Use the help of right triangle figure to find the ratio
tan α = 5/12
side in front of the angle/ side adjacent to the angle = 5/12
Draw the figure, see image attached

Using pythagorean theorem, we find the length of the hypotenuse is 13
sin α = side in front of the angle / hypotenuse
sin α = -12/13

cos α = side adjacent to the angle / hypotenuse
cos α = -5/13

Determine ratio of ∠β
sin β = -1/2
sin β = sin 210° (third quadrant)
β = 210°

$cos \beta = -\frac{1}{2} \sqrt{3}$

$tan \beta= \frac{1}{3} \sqrt{3}$

SECOND PART
Solve the questions
Find sin (α + β)
sin (α + β) = sin α cos β + cos α sin β
$sin( \alpha + \beta )=(- \frac{12}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{5}{13} )( -\frac{1}{2} )$
$sin( \alpha + \beta )=(\frac{12}{26}\sqrt{3})+( \frac{5}{26} )$
$sin( \alpha + \beta )=(\frac{5+12\sqrt{3}}{26})$

Find cos (α - β)
cos (α - β) = cos α cos β + sin α sin β
$cos( \alpha + \beta )=(- \frac{5}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{12}{13} )( -\frac{1}{2} )$
$cos( \alpha + \beta )=(\frac{5}{26} \sqrt{3})+( \frac{12}{26} )$
$cos( \alpha + \beta )=(\frac{5\sqrt{3}+12}{26} )$

Find tan (α - β)
$tan( \alpha - \beta )= \frac{ tan \alpha-tan \beta }{1+tan \alpha tan \beta }$
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{1+(\frac{5}{12}) ( \frac{1}{2} \sqrt{3})}$

Simplify the denominator
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{1+(\frac{5\sqrt{3}}{24})}$
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }$

Simplify the numerator
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{6}{12} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }$
$tan( \alpha - \beta )= \frac{ \frac{5-6\sqrt{3}}{12} }{ \frac{24+5\sqrt{3}}{24} }$

Simplify the fraction
$tan( \alpha - \beta )= (\frac{5-6\sqrt{3}}{12} })({ \frac{24}{24+5\sqrt{3}})$
$tan( \alpha - \beta )= \frac{10-12\sqrt{3} }{ 24+5\sqrt{3}}$

7 0

2 years ago

A metal shipping container is being used to transport clothes overseas. It will have a volume of 640 cubic feet. If the length o

Lilit [14]

Answer:

C. 128ft

Step-by-step explanation:

it's C because whenever it says and you're supposed to multiply always remember that :) = (which means area ofc) you're finding the so you multiply 16x8 and the you get your answer (: ignore the 640 you just focus on the 16 and 8 ok? 16x8=128! :))

 >:(

3 0

3 years ago

At a concession stand, a pickle and two bags of chips costs a total of $3.25. Three pickles and four bags of chips costs a total

kolbaska11 [484]

Answer:

A bag of chips costs $1

A pickle costs $1.25

Step-by-step explanation:

P + 2c = 3.25 Start with these two equations

3p + 4c = 7.25

p = -2c + 3.25 Solve for one variable

3(-2c +3.25) + 4c = 7.25 Substitute

-6c + 9.75 + 4c = 7.25

-2c = -2

c = 1

p + 2(1) = 3.25 Substitute

p + 2 = 3.25

p = 1.25

4 0

3 years ago

Safari isn’t helping so please help!!

Pepsi [2]

third option is the correct answer....

3 0

3 years ago

Given the function f(3) = 36 complete the following table​

Given the function f(3) = 36 complete the following table