The length of side c will be 2 m.
Median: 89
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From A draw the altitude AH intersecting BC in H
Let's prove that triangle ABH is congruent to triangle ACH
The above 2 triangles are right triangles due to the altitude AH
Angle B= Angle C (given)
Angle AHB = Angle AHC =90° (since AH is the altitude)
Then angle BAH = CAH (both complementary to B & C respectively
And AH is a common side
Now Tri. ABH = Tri. ACH because ASA, hence AB=AC
Scientific notation is just a form of the number:
And the format is:
(A number greater than 1 but less than 10) times (10 to the power of x) ,where x can be positive or negative, but not a fraction or decimal
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