Answer:
Step-by-step explanation:
Tricky. Very neat.
You are missing the minor arcAC and you need it, but don't fret. It can be found.
The formula for this is x = 1/2(Major Arc(235) - Minor Arc(see below) )
The minor arc is the supplement of x.
The minor arc is also equal to the the central angle
So the minor arc is 180 - x
x = 1/2 (235 - (180 - x) ) Remove the inside brackets
x = 1/2 (55 + x ) Remove the remaining brackets
x = 1/2 *55 + 1/2x Subtract 1/2x from both sides
1/2 x = 27.5 Multiply both sides by 2
x = 55
Answer:
the second one
Step-by-step explanation:
because g(x) and f(x) is bout the same
The statement is true.
Answer: Option 1.
<u>Explanation:</u>
An horizontal beam is constantly flat and has a consistent cross-segment. Notwithstanding normal shaft parameters, bar has the accompanying properties: Direction. A flat shaft might be situated either along the worldwide X-hub or worldwide Y-pivot.
A horizontal beam is used to hold a building up right and to give the support to the building. But the length of the horizontal beam differs in an inverse way between the supports.
Given side length "a" and angle "A", calculate the diagonals<span><span>
p = square root [( 2a^2 - 2a^2 cos(A) )]
</span>q = </span><span>square root [( 2a^2+ 2a^2 cos(A) )]</span>
http://www.calculatorsoup.com/calculators/geometry-plane/rhombus.php
side = 36
cos (32) = 0.84805
p = <span>small diagonal = </span>
<span>
<span>
<span>
19.8457652914
</span>
</span>
</span>
<span><span>
</span>
</span>
q =
large diagonal =
<span>
<span>
<span>
69.2108777578
</span>
</span>
</span>
Answer:
There are no like terms.
Step-by-step explanation:
