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3 years ago

5

The population of a city decreases by 0.6% per year. What should we multiply the current population by to find next year's popul

ation in one step?

1 answer:

Agata [3.3K]3 years ago

3 0

Answer:

0.994

Step-by-step explanation:

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Help Me Plz!!!!!!!!!!!!!

Strike441 [17]

Answer:

$a = 6\sqrt 3,\:\:b =12,\:\:c=6\sqrt 2$

Step-by-step explanation:

$by \: 30 \degree - 60 \degree - 90 \degree \: theorem \\ \\ 6 = \frac{1}{2} b\\ \\ 6 \times 2 = b \\ \\ 12 = b \\ \\ \huge\red {\boxed {b= 12}} \\ \\ a = \frac{ \sqrt{3} }{2} b \\ \\ a = \frac{ \sqrt{3} }{2} \times 12 \\ \\ \huge\purple {\boxed {a = 6 \sqrt{3}}} \\ \\ c = \frac{1}{ \sqrt{2} } b \\ \\ c = \frac{1}{ \sqrt{2} } \times 12 \\ \\ c = \frac{ \sqrt{2} }{2} \times 12 \\ \\ \huge\orange {\boxed {c = 6 \sqrt{2}}} \\ \\$

8 0

3 years ago

I need help on this. The portrait studio can buy photographs on canvas. The small canvas photograph print is $20 and the large c

Whitepunk [10]

<h3>Answer:</h3>

6 large prints
12 small prints

<h3>Step-by-step explanation:</h3>

<em>Numerical Reasoning</em>

Consider a set of prints that consists of 2 small prints and one large print (that is, twice as many small prints as large). The value of that set will be ...

... 2×$20 +45 = $85

To have revenue of at least $510, the studio must sell ...

... $510/$85 = 6

sets of prints. That is, the studio needs to sell at least 6 large prints and 12 small ones.

_____

<em>With an equation</em>

Let x represent the number of large prints the studio needs to sell. Then 2x will represent the number of small prints. Total sales will be ...

... 20·2x +45·x ≥ 510

... 85x ≥ 510

... x ≥ 510/85

... x ≥ 6

The studio needs to sell at least 6 large prints and 12 small prints.

8 0

3 years ago

An airplane flies due north from ikeja airport for 500km.It then flies on a bearing of 060 from a further distance of 300km befo

Nata [24]

Answer:

482 km

63.94 degrees

Step-by-step explanation:

to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.

Cosine rule states that

C = $\sqrt{A^{2} + B^{2} -2AB cos(c) }$

where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060

solving now, we have

C = $\sqrt{500^{2} + 300^{2} -2 * 500 * 300 cos(60) }$

C = $\sqrt{250000 + 90000 - [215000 cos(60) }]$

C = $\sqrt{340000 - [215000 * 0.5 }]$

C = $\sqrt{340000 - [107500 }]$

C = $\sqrt{232500}$

C = 482 km

The bearing can be gotten by using the Sine Rule.

$\frac{sina}{A}$ = $\frac{sinc}{C}$

sina/500 = sin60/482

482 sina = 500 sin60

sina = $\frac{500 sin60}{482}$

sina = 0.8983

a = sin^-1(0.8983)

a = 63.94 degrees

6 0

3 years ago

A pail holds 6 3/4 gallons of water. How much is this in cups? Write your answer as a whole number or a mixed number in simplest

bonufazy [111]

The pail holds 108 cups of water.

3 0

3 years ago

Solve the system by the elimination method.<br> 16x-3y=-1<br> -8x+y=3

mojhsa [17]

Send me your email I will send the working.

The answers:
x = 1
y = -5

7 0

3 years ago