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Schach [20]
3 years ago
10

For an object to be seen, light must leave ___ and enter ___.

Chemistry
1 answer:
laila [671]3 years ago
6 0

Answer:

C

Explanation:

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Una masa de aire ocupa un volumen de5litro a una temperatura de 120c Cual será el nuevo volumen si la temperatura se reduce ala
zalisa [80]

Answer:

1. V_2=2.5L

2. V_2=8000mL

3. V_2=176.3L

Explanation:

¡Hola!

En este caso, dada la información para estos problemas, procedemos de la siguiente manera, basado en las leyes de los gases ideales:

1. Una masa de aire ocupa un volumen de 5 litros a una temperatura de 120 °C Cual será el nuevo volumen si la temperatura se reduce a la mitad:

Aqui, utilizamos la ley de Charles, asegurándonos que la temperatura está en Kelvin:

\frac{T_2}{V_2} =\frac{T_1}{V_1} \\\\V_2 =\frac{V_1T_2}{T_1} \\\\V_2 =\frac{5L*196.5K}{393K} \\\\V_2=2.5L

2. Un gas ideal ocupa un volumen de 4000 ml a una presión absoluta de 1500 kilo pascal Cual será la presión si el gas es comprimido lentamente hasta 750 kilo pascal a temperatura constante?

Aquí, utilizamos la ley de Boyle, dado que la temperatura se mantiene constante, calculando el volumen, ya que lo que se da es la presión final:

\neq P_2V_2=P_1V_1\\\\V_2=\frac{P_1V_1}{P_2}\\\\ V_2=\frac{4000mL*1500kPa}{750kPa}\\\\V_2=8000mL

3. Un gas ocupa un volumen de 200 litros a 95°C y 782 mmHg Cual será el volumen ocupado por dicho gas a 65°C y 815 mmHg:

Aquí, utilizamos la ley combinada de los gases ideales, asegurándonos que las temperaturas están en Kelvin:

\frac{T_2}{P_2V_2} =\frac{T_1}{P_1V_1} \\\\V_2 =\frac{P_1V_1T_2}{P_2T_1} \\\\V_2 =\frac{782mmHg*200L*338K}{815mmHg*368K}\\\\V_2=176.3L

¡Saludos!

6 0
3 years ago
What ions and/or molecules (apart from water) are present in relatively large proportions in a solution of a weak acid hclo (aq)
matrenka [14]

HClO, perchloric acid is a weak acid. Unlike strong acids like HCl or H2SO4 it not dissociate completely but partially such that an equilibrium exists between the dissociated ions and the undissociated acid. The equilibrium is as shown below:

HClO + H2O ↔ H3O⁺ + ClO⁻

Since HClO is a weak acid, the reverse reaction is favored over the forward reaction. Thus apart from water, HClO will be present in large amounts.

3 0
3 years ago
A sample of an unknown compound has a percent composition of 52.14% carbon, 13.13% hydrogen, and 34.73% oxygen. Which compounds
Artemon [7]
<h3>Answer:</h3>

                The two possible compounds are;

                            1) Dimethyl Ether H₃C--O--CH₃

                           2) Ethanol  H₃C--CH₂--OH

<h3>Solution:</h3>

Step 1: Calculate Moles of each Element;

                      Moles of C  =  %C ÷ At.Mass of C

                      Moles of C  =  52.14 ÷ 12.01

                      Moles of C  =  4.341 mol


                      Moles of H  =  %H ÷ At.Mass of H

                      Moles of H  =  13.13 ÷ 1.01

                      Moles of H  =  13.00 mol


                      Moles of O  =  %O ÷ At.Mass of O

                      Moles of O  =  34.73 ÷ 16.0

                      Moles of O  =  2.170 mol

Step 2: Find out mole ratio and simplify it;

                C                                        H                                     O

            4.341                                 13.00                              2.170

     4.341/2.170                      13.00/2.170                    2.170/2.170

               2                                      5.99                                    1

               2                                        6                                       1

Hence,  Empirical Formula  =  C₂H₆O

<h3>Result:</h3>

         As the molecular mass of compound is not given therefore, we can assume and guess the empirical formula to be the molecular formula. Hence, possible compounds are,

                            1) Dimethyl Ether H₃C--O--CH₃

                           2) Ethanol  H₃C--CH₂--OH

3 0
3 years ago
Mass is measured against a standard using a
Tamiku [17]
The answer is a balance
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About how many miles on Earth are equal to one degree of latitude?
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The answer would be 69 miles
6 0
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