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lapo4ka [179]
2 years ago
7

Please answer in details. what class of carbon is coal ​

Chemistry
1 answer:
klio [65]2 years ago
4 0
Coal falls under Graphite
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Describe the motion of molecules in an ice cube and in a radiator in winter
KIM [24]
The motion of molecules in a ice cube are so packed together that they can't move freely like molecules in liquids and gases
8 0
2 years ago
Read 2 more answers
The label shown above contains information about some harmful effects of acetone.A group of students plans to use acetone to rin
Fed [463]

Answer:

<u>Heating water with an open flame</u>

<u>Explanation:</u>

Remember, we are told in the label that Acetone is a "flammable liquid and vapor." <em>Being flammable means the substance can easily be set on fire</em>, and we would expect an open flame from heating water to trigger an explosion (a disaster) in which the Acetone is set on fire causing life-threatening dangers to the second group of students.

8 0
3 years ago
S<br> SIO₂ +3C Sic +20o<br> Sic ? mass in grams<br> С c-
seraphim [82]

Answer:

26.74g

Explanation:

The equation of the reaction is;

SIO₂ + 3C --> SiC +2CO

From the balanced equation, the relationship between SiC and C is;

3 mol of C produces 1 mol of SiC

Converting mol to mass using; Mass = moles * Molar mass

Mass of SiC = 1 mol * 40.11 g/mol = 40.11g

This means;

3 mol of C produces 40.11g of SiC

2 mol of C produces xg of SiC

3 = 40.11

2 = x

x = 2 * 40.11 / 3 = 26.74g

6 0
3 years ago
Which of the following describes a characteristic of water that makes it cohesive in nature?
kari74 [83]

Answer:

D is answer

Explanation:

8 0
2 years ago
**PLEASE SHOW YOUR WORK**Calculate how much energy would be necessary to convert 250.0 grams of ice at -30°C to steam at 145°C.
garri49 [273]

Answer:

Q= mc∆T(ice) + mLF(ice) + mc∆T(water) + mLV(water) + mc∆T(steam)

m=250 g = 0.25 kg = ¼ kg c(ice)= 2100 J/kg.K c(water)= 4200 J/kg.K LF(ice)= 333.7 kJ/kg LV(water)= 2256 kJ/kg c(steam)= 2080 J/kg.K

Explanation:

Q= ¼ × 2100 × (0°-(-30°)) + ¼ × 333700 + ¼ × 4200 × (100°-0°) + ¼ × 2256000 + ¼ × 2080 × (145°-100°)

Q= 15750 + 83425 + 105000 + 564000 + 23400

Q= 791575 J

7 0
2 years ago
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