I believe it is mono-lateral because most animals are divided in half at the spine.
<span>Fe2O3 + 3CO --> 2Fe + 3CO2
</span><span>
m(Fe2O3)=213 g
m(CO)=140 g
</span>_______________
<span>n(Fe2O3)=?
m(Fe)=?
n(Fe2O3)=?
n(CO)=?
n(CO2)=?
</span>
<span>n(Fe2O3)=m(Fe2O3) / M(Fe2O3)
n(Fe2O3)= 213 g / 159,7 gmol-1 = 1,33 mol
</span>
<span>n(CO)= m(CO) / M(CO)
n(CO)= 140 g / 28,01 gmol-1 = 4,99 mol</span>
54.936 grams of NaCl will be produced from 33.0 g of Na and 34.0 g of Cl.
Explanation:
Data given:
mass of Na = 33 grams
mass of 
= 24 grams
atomic mass of Na = 23 grams/moles
atomic mass of Cl = 70 grams/mole
mass of NaCl formed =?
atomic mass of NaCl = 58.44 gram/mole
balanced chemical reaction:
2Na + ⇒ 2NaCl
number of moles = 
putting the values in the equation:
number of moles of Na = 
= 0.69 moles
number of moles of chlorine gas = 
= 0.47 moles
limiting reagent is chlorine gas in the reaction
from the balanced chemical reaction:
1 mole of chlorine gas reacts to form 2 moles of NaCl
then 0.47 moles of chlorine gas will form x moles
= 
x = 0.94 moles of NaCl is formed.
mass = atomic mass x number of moles
mass = 58.44 x 0.94
= 54.936 grams of NaCl is produced.
Chemical reaction: Sr(OH)₂ + 2HNO₃ → Sr(NO₃)₂ + 2H₂O.
part A) m(Sr(OH)₂) = 21,78 g.
n(Sr(OH)₂) = m(Sr(OH)₂) ÷ M(Sr(OH)₂).
n(Sr(OH)₂) = 21,78 g ÷ 87,62 g/mol.
n(Sr(OH)₂) = 0,248 mol.
c(Sr(OH)₂) = n(Sr(OH)₂) ÷ V(Sr(OH)₂).
c(Sr(OH)₂) = 0,248 mol ÷ 0,075 L.
c(Sr(OH)₂) = 3,3 mol/L.
part B) V(Sr(OH)₂) = 34,21 mL = 0,03421 L.
n(Sr(OH)₂) = 0,03421 L · 3,3 mol/L = 0,112 mol.
From chemical reaction: n(Sr(OH)₂) : n(HNO₃) = 1 : 2.
n(HNO₃) = 0,225 mol.
V(HNO₃) = 0,225 mol ÷ 0,25 mol/L.
V(HNO₃) = 0,9 L = 900 ml.
The hotter water is less dense and rises. The cooler water then sinks because it is more dense.
