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torisob [31]
3 years ago
5

Calculate the number of moles of BaF2 in a 10.0 g sample of BaF2.

Chemistry
2 answers:
kari74 [83]3 years ago
6 0

Answer:

0.06moles

Explanation:

I did this question already and I got it right.

UkoKoshka [18]3 years ago
5 0

Answer:

The number of moles = 0.06 moles

Explanation:

i) Formula

Number of moles = Mass of the sample ÷ Molar masses of the substances

ii) Number of moles = 10.0 ÷ (137)+(19×2)

= 10.0 ÷ 175

= 0.06 moles

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How many moles of lithium chloride will be formed by the reaction of chloride with 4.28 mol of lithium bromide in the following
lys-0071 [83]

Answer:

The answer is 4.28 moles

Explanation:

This is super easy okay, you won't forget this!

Basically mole ratios, we're just looking at the coefficients in front of the compounds, multiplying them, and dividing them as we see fit.

In this example, you can see how you need 2 moles of lithium bromide (LiBr) for the reaction, and 2 moles of lithium chloride (LiCl) will be produced.

Basically, the <u>molar ratio</u> is when you divide numbers and see how much of this do I have for that (if that makes sense).

So if you were to divide the 2 moles of LiBr / 2 moles of LiCl = 1. So we know that the mole ratio for LiBr to LiCl is 1:1 or 2:2, either or, it's the same thing.

SO THE BIG IDEA, if we have 4.28 moles of lithium bromide reacting, we should also have 4.28 moles of lithium chloride produced, BECAUSE the <u>mole ratio</u> is 1:1.

I hope this makes sense please tell me if it doesn't, I will try my best to explain a little more.

7 0
2 years ago
Please help me! Please explain!
Ksju [112]

Answer: Total number of Protons PLUS Neutrons

Explanation:

Hopes that helps

8 0
2 years ago
O
baherus [9]
The answer is the first one I think
8 0
2 years ago
A chemist prepares a solution of silver nitrate by measuring out of silver nitrate into a volumetric flask and filling the flask
Snezhnost [94]

Amount of silver nitrate taken = 269.μmol AgNO_{3}

Volume of the solution = 300. mL

Concentration of a solution is generally expressed in terms of molarity. Molarity is defined as the moles of a substance present per liter of the solution.

Molarity = \frac{Moles of solute}{Volume of solution(L)}

We want the concentration in millimoles/L.

Converting μmol to millimol solute:

269.μmol * \frac{1 millimol}{1000 micromol} = 0.269 millimol

Volume from mL to L: 300. mL * \frac{1 L}{1000 mL} = 0.300 L

Therefore concentration of the chemist's solution = \frac{0.269 millimol}{0.300 L} =  0.897 \frac{millimol}{L}

8 0
3 years ago
HELP FAST!! 20 POINTS!! Any one of these please!!!
Ann [662]
Not sure about the first two but I think number three is B. sorry if I'm wrong
6 0
3 years ago
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