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shutvik [7]
3 years ago
10

Pls help ASAP NUMBER 2

Mathematics
2 answers:
Lisa [10]3 years ago
5 0

Answer:

The answer to the question is 2 and 5

Oksana_A [137]3 years ago
5 0
I believe it is H, i hope i am right! but good luck
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Given the function f(x) x^2-2x/x^3 +9x^2-10x Find any holes, vertical asymptotes, and horizontal asymptotes there may be.
yulyashka [42]

Answer:

See below

Step-by-step explanation:

I assume you mean f(x)=\frac{x^2-2x}{x^3+9x^2-10x}:

Holes: Since f(x)=\frac{x^2-2x}{x^3+9x^2-10x} reduces to f(x)=\frac{x(x-2)}{x(x^2+9x-10)}, then there is a hole at x=0 as x exists in both the numerator and denominator (however, its limit as x approaches 0 is 1/5).

Vertical Asymptotes: If we further reduce f(x)=\frac{x(x-2)}{x(x^2+9x-10)} to f(x)=\frac{x-2}{(x+10)(x-1)}, then we see that there are vertical asymptotes at x=-10 and x=1

Horizontal Asymptotes: As the degree of the numerator is less than the degree of the numerator (2), then there is a horizontal asymptote at y=0

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