Answer:
A.
= Cube root of 4.
Step-by-step explanation:
We have been given an expression
. We are asked to find the equivalent expression for our given expression.
Using exponent property
, we will get,
![2^{\frac{2}{3}}=\sqrt[3]{2^2}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B2%5E2%7D)
![2^{\frac{2}{3}}=\sqrt[3]{4}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B4%7D)
Upon looking at our given choices, we can see that option A is the correct choice.
Since you have a angle number of 23 and you see the tiny square that means it’s equal to 90 up top and add 23 and 90 together and then subtract that by 180 to get all 3 angles in the triangle and then just use that to find the other line that’s 180.
10x8? 80. 10, 20, 30, 40, 50, 60, 70, 80
1. Make an equation.
Moving company #1: y = 17x + 840
Moving company #2: y = 22x + 760
2. Put the equations together and solve
17x + 840 = 22x + 760
-17x -17x
840 = 5x + 760
-760 -760
80 = 5x
5 5
16 = x
When a job is 16 hours they both charge the same thing.
Answer:
Vertical component of velocity is ![81.35 ft/sec.](https://tex.z-dn.net/?f=81.35%20ft%2Fsec.)
Horizontal component of velocity is
.
Step-by-step explanation:
Horizontal component of velocity is defined as:
![v_{x} = v\times cos\theta](https://tex.z-dn.net/?f=v_%7Bx%7D%20%3D%20v%5Ctimes%20cos%5Ctheta)
Vertical component of velocity is defined as:
![v_{y} = v\times sin\theta](https://tex.z-dn.net/?f=v_%7By%7D%20%3D%20v%5Ctimes%20sin%5Ctheta)
Where
are the horizontal and vertical components of velocity.
is the actual velocity and
is the angle with horizontal axis at which the object was thrown.
Here, we are provided with the following:
![v = 200 ft/sec](https://tex.z-dn.net/?f=v%20%3D%20200%20ft%2Fsec)
![\theta = 24^\circ](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2024%5E%5Ccirc)
![v_{x} = 200 \times cos24^\circ\\\Rightarrow 200 \times 0.913\\\Rightarrow v_{x} = 182.6 ft/sec](https://tex.z-dn.net/?f=v_%7Bx%7D%20%3D%20200%20%5Ctimes%20cos24%5E%5Ccirc%5C%5C%5CRightarrow%20200%20%5Ctimes%200.913%5C%5C%5CRightarrow%20v_%7Bx%7D%20%3D%20182.6%20ft%2Fsec)
![v_{y} = 200 \times sin24^\circ\\\Rightarrow 200 \times 0.407\\\Rightarrow v_{y} = 81.35 ft/sec](https://tex.z-dn.net/?f=v_%7By%7D%20%3D%20200%20%5Ctimes%20sin24%5E%5Ccirc%5C%5C%5CRightarrow%20200%20%5Ctimes%200.407%5C%5C%5CRightarrow%20v_%7By%7D%20%3D%2081.35%20ft%2Fsec)
So, Vertical component of velocity is ![81.35 ft/sec.](https://tex.z-dn.net/?f=81.35%20ft%2Fsec.)
Horizontal component of velocity is
.