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SVEN [57.7K]
3 years ago
11

How are scents or fragrances used in cosmetology? Why would a cosmetologist need to be aware of scents and fragrances?

Chemistry
2 answers:
bekas [8.4K]3 years ago
5 0
Used in perfumes, face washes, lotions, shampoos, conditioners, etc. They need to be aware because if a perfume had a scent that did not smell right or "pretty" then noone would want to buy their product.

svp [43]3 years ago
4 0

Explanation: Scents or fragrances are one of the important factors that affects the people's choice of cosmetic products. Some examples of fragrance products are aftershave, cologne, perfume etc. Fragrance products are also used in personal care products such as shower gel, shaving cream, shampoo etc.

It is important for a cosmetologist to be aware of scents and fragrances as it contribute to people's personal hygiene, self-esteem and people's individuality and also it can help the cosmetologist to use the type of fragrance that can attract people to buy the product.

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If an unknown element displays many extremely strong metallic properties, where is it most likely to be located on the periodic
dalvyx [7]
It is placed on the far left. Hope I helped:)

3 0
3 years ago
Read 2 more answers
In substitution reactions, (CH3)3C-I reacts at the same rate with Br- and Cl- even though Br- is a more reactive nucleophile tha
Kamila [148]

Answer:

A. (CH3)3C-I reacts by SN1 mechanism whose rate is independent of nucleophile reactivity.

Explanation:

We must recall that (CH3)3C-I is a tertiary alkyl halide. Tertiary alkyl halides preferentially undergo substitution reaction via SN1 mechanism.

In SN1 mechanism, the rate of reaction depends solely on the concentration of the alkyl halide (unimolecular mechanism) and is independent of the concentration of the nucleophile. As a result of this, both Br^- and Cl^- react at the same rate.

5 0
3 years ago
This is the balances equations. C3H8 + 5O2 → 3CO2 + 4H2O How many moles of oxygen are required to produce 37.15 g CO2
AleksandrR [38]
Molar mass O2 = 31.99 g/mol

Molar mass CO2 = 44.01 g/mol

Moles ratio:

<span>C3H8 + 5 O2 = 3 CO2 + 4 H2O 
</span>
5 x 44.01 g O2 ---------------- 3 x 44.01 g CO2
( mass of O2) ------------------ 37.15 g CO2

mass of O2 = 37.15 x 5 x 44.01/ 3 x 44.01

mass of O2 = 8174.8575 / 132.03

mass of O2 = 61.916 g 

Therefore:

1 mole O2 ----------------- 31.99 g
moles O2 -------------------- 61.916

moles O2 = 61.916 x 1 / 31.99

moles = 61.916 / 31.99 => 1.935 moles of O2
4 0
4 years ago
Identify the Brønsted-Lowry acid, the Brønsted-Lowry base, the conjugate acid, and the conjugate base in each reaction:
ExtremeBDS [4]

Answer:

C5H5N is the base and C5H5NH+ is the conjugate acid

H2O is the acid and OH− is the conjugate base

Explanation:

<u>Hydrogen + is also called a proton</u>

C5H5N is the base because it receives the proton (H+) and C5H5NH+ is its conjugate acid

H2O is the acid  because it gives up the proton and OH− is the conjugate base because it is capable of receiving the proton

Answer:

HNO3 is the acid and NO3- is the conjugate base

H2O is the base and H3O+ is the conjugate acid

Explanation

HNO3 is the acid and NO3− is its conjugate base, capable of receiving a proton

H2O is the base because it receives the proton and H3O+ is a conjugate acid capable of giving up the proton.

3 0
3 years ago
GR 11 CHEM M3
galina1969 [7]

<em>A:  When burning Sulfur, Sulfur Dioxide is released. Having more Oxygen available provides more reactive potential for the burning Sulfur, making it burn much more fiercely. In water, the Sulfur Dioxide forms Sulfurous acid. Added: 12 years ago.</em>

<em />

<em>Explanation:</em>

<h3><em /></h3>
6 0
3 years ago
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