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kirill [66]
3 years ago
8

Read the excerpt from Heart of a Samurai.

Mathematics
2 answers:
andrey2020 [161]3 years ago
6 0

Answer:

D

Step-by-step explanation:

The snail's path is the only thing vividly described in this text.

Mazyrski [523]3 years ago
4 0

Answer: D. the snail’s path

Step-by-step explanation: because The author uses the most precise words to describe the snail's path.

This excerpt has been taken from Heart of a Samurai, a historical novel written by Margi Preus in 2010. Precise words such as 'shiny', 'ribbon' and 'unfurling' have been used in the second sentence to describe the path of the snail, which is a small animal that has a wet body and moves very slowly. In other words, the author describes the way the path looks by establishing a comparison between the path and a shiny ribbon.

Hope this help

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The sum of two numbers is odd. Can the quotient of the two numbers be an odd number?
Natalka [10]

Answer: No.

Step-by-step explanation:

I guess that here we have the statement:

If the sum of two numbers is odd----> can their quotient be an odd number?

first, for n an integer number, we have that:

an odd number can be written as 2n + 1

an even number can be written as 2n.

The sum of two numbers is only odd if one of them is odd and the other even.

Then we have a number that is 2n and other that is 2k + 1, for n and k integer numbers.

Now, let's see if the quotient can also be an odd number.

One way to think this is:

There is an odd number such that when we multiply it by another odd number, the result is an even number?

no, and i can prove it as:

let 2k + 1 be an odd number, and 2j + 1 other.

the product is:

(2k + 1)*(2j + 1) = 2*(2*k*j + k + j) + 1

and as k and j are integers, also does 2*k*j + k + j, so:

2*(2*k*j + k + j) + 1 is an odd number.

This says that the product of two odd numbers is always odd, then we never can have that the quotient between an even number and an odd number is odd.

4 0
3 years ago
4.72x10^10 Please I need help fast
vodka [1.7K]

Answer:

The answer is 47200000000

5 0
2 years ago
\large -6x+6y=6<br> \large 6x+3y=12
Kaylis [27]

Answer:

the solution of the system is:

x = 1 and y = 2.

Step-by-step explanation:

I suppose that we want to solve the equation:

-6*x + 6*y = 6

6*x + 3*y = 12

To solve this, we first need to isolate one of the variables in one of the equations.

Let's isolate y in the first equation:

6*y = 6 + 6*x

y = (6 + 6*x)/6

y = 6/6 + (6*x)/6

y = 1 + x

Now we can replace this in the other equation:

6*x + 3*(1 + x) = 12

6*x + 3 + 3*x = 12

9*x + 3 = 12

9*x = 12 - 3 = 9

x = 9/9 = 1

Now that we know that x = 1, we can replace this in the equation "y = 1 + x" to find the value of y.

y = 1 + (1)  = 2

Then the solution of the system is:

x = 1 and y = 2.

6 0
3 years ago
Need answer ASAP<br><br><br><br><br> Express a 10/3 b 7/3 in simplified radical form.
anastassius [24]
I guess this is what you mean     3√a^10      and 3√b^7
5 0
3 years ago
2 ft
sdas [7]

Answer:

88/7 ft = 12.6 ft (nearest tenth)

Step-by-step explanation:

Circumference of a circle = 2\pir

<u>Radius of inner circle</u>

Given:

  • circumference of inner circle = 22ft
  • \pi = 22/7

⇒ 22 = 2 x (22/7) x r

⇒ r = 3.5

So the radius of the inner circle is 3.5 ft

<u>Radius of outer circle</u>

If the distance between the inner circle and the outer circle is 2 ft, then the radius of the outer circle = 3.5 + 2 = 5.5

<u>Circumference of outer circle</u>

Therefore, circumference of outer circle:

=  2 x (22/7) x 5.5

= 242/7 ft

<u>Difference between circumferences</u>

Difference = outer circle circumference - inner circle circumference

                  = 242/7 - 22

                  = 88/7 ft

                  = 12.6 ft (nearest tenth)

4 0
2 years ago
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