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denis23 [38]
3 years ago
5

Evaluate the expression when m= -2

Mathematics
1 answer:
ZanzabumX [31]3 years ago
7 0

Answer:

im not positive but i think if im wrong then tell me

Step-by-step explanation:

Solution :

mn + m + n + 1

= m( n + 1 ) + 1( n + 1 )

= ( n + 1 )( m + 1 )

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Hey there!

Great question:)


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2 x 10 + 4 x 1 + (7 x 1/10) + (4 x 1/100) + (5 x 1/1000) in standard form
Verizon [17]

Answer:

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weeeeeb [17]

Answer:

16,25,30,49

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Step-by-step explanation:

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3 years ago
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nignag [31]

For this problem, the confidence interval is the one we are looking for. Since the confidence level is not given, we assume that it is 95%.

 

The formula for the confidence interval is: mean ± t (α/2)(n-1) * s √1 + 1/n


Where:

<span>
</span>

α= 5%


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t 0.025, 19 = 2.093 (check t table)


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df = n – 1 = 20 – 1 = 19

So plugging in our values:


8.41 ± 2.093 * 0.77 √ 1 + 1/20


= 8.41 ± 2.093 * 0.77 (1.0247)


= 8.41 ± 2.093 * 0.789019


= 8.41 ± 1.65141676


<span>= 6.7586 < x < 10.0614</span>

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2 years ago
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8 0
3 years ago
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