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Aleonysh [2.5K]
3 years ago
12

Help please Calculate the product of 8/15, 6/5, and 1/3. 

Mathematics
1 answer:
bogdanovich [222]3 years ago
4 0

Hey there!

Great question:)


8/15 * 6/5 * 1/3 = 16/75


I hope this helps;)

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Part 1 state the domain and range of the given relation.
hram777 [196]
A relation is any set of ordered pairs, which can be thought of as (input, output).

A function is a relation in which NO two ordered pairs have the same first component and different second components.

The set of first components (x-coordinates) in the ordered pairs is the DOMAIN of the relation.

The set of second components (y-coordinates) is the RANGE of the relation.

Part 1:
Domain: {-1, 1, 3, 6}
Range: {2, 2, 2, 2}

Part 2:
To determine whether the given relation represents a function, look at the given relation and ask yourself, “Does every first element (or input) correspond with EXACTLY ONE second element (or output)?”

Remember that a function can only take on 1 output for each input.

It helps to plot the points on the graph and perform the Vertical Line Test (VLT):

The Vertical Line Test allows us to know whether or not a graph is actually a function. If a vertical line intersects the graph in all places at exactly one point, then the relation is a function.

As you can see in the attached screenshot, every vertical line drawn only has 1 point in it. This means that each x-value corresponds to exactly one y-value. The given relation passed the VLT. Therefore, the relation is a function.


Please mark my answers as the Brainliest if you find my explanation helpful :)

5 0
3 years ago
a wildlife center presents a program about birds of prey. the center charges a basic fee of $325 and an additional fee for each
Rainbow [258]

The exhibition of 7 birds will cost $2,450

<h3>How to calculate the total cost ?</h3>

The wildlife center charges a basic fee of $325 for a bird exhibition

When 5 birds were exhibited, $125 additional fee was charged

The additional fee for a bird is

= 125/5

= 25

Therefore the total cost of exhibiting 7 birds can be calculated as follows

= 325 + 25

= 350

350 × 7

= 2,450

Hence the total cost for the exhibition of 7 birds is $2,450

Read more on total cost here

brainly.com/question/771102?referrer=searchResults

#SPJ1

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=%2832%29%5E%7B1%2F5%7D" id="TexFormula1" title="(32)^{1/5}" alt="(32)^{1/5}" align="absmiddle"
lorasvet [3.4K]

Answer:

<h2><em><u>2</u></em></h2>

Step-by-step explanation:

{32}^{ \frac{1}{5} }

=  \sqrt[5]{32}

=  \sqrt[5]{2 \times 2 \times 2 \times 2 \times 2}

= <em><u>2</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

4 0
3 years ago
What is the mean absolute deviation of the data set?
neonofarm [45]

Answer:

<u>B. 2</u>

To find MAD, find the mean of the set, then find how far each number is from the mean. Next, find the mean of THAT set of numbers. Yea, I know it's a bit confusing... don't worry!

Find the mean of the set:

12 + 10 + 10 + 8 + 6 + 7 + 7 + 12

72

72 / 8

<u>9</u>

Find how far each number is from 9:

12 - 9 = <u>3</u>

10 - 9 = <u>1</u>

10 - 9 = <u>1</u>

9 - 8 = <u>1</u>

9 - 6 = <u>3</u>

9 - 7 = <u>2</u>

9 - 7 = <u>2</u>

12 - 9 = <u>3</u>

Find the mean of that number set:

{3, 1, 1, 1, 3, 2, 2, 3}

3 + 1 + 1 + 1 + 3 + 2 + 2 + 3

16

16 / 8

<u>2</u>

<u>So the answer is 2!</u>

Not so hard after all   :D

7 0
3 years ago
Read 2 more answers
What binomial do you have to add to the polynomial:
marshall27 [118]

Answer:

a)  -2x^2+5xy

b)  -3y^2+5xy

Step-by-step explanation:

<u>Part (a)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable x is:

-2x^2+5xy

(2x^2+3y^2-5xy+1)+(-2x^2+5xy)

=2x^2+3y^2-5xy+1-2x^2+5xy

=2x^2-2x^2+3y^2-5xy+5xy+1

=3y^2+1

<u>Part (b)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable y is:

-3y^2+5xy

(2x^2+3y^2-5xy+1)+(-3y^2+5xy)

=2x^2+3y^2-5xy+1-3y^2+5xy

=2x^2+3y^2-3y^2-5xy+5xy+1

=2x^2+1

7 0
2 years ago
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