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3 years ago

1. Find the distance from A to B. Explain how you found this distance.

Mathematics

1 answer:

DiKsa [7]3 years ago

8 0

Answer:

i booper you fat you hahahhaha class of living noob this?

Step-by-step explanation:

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3y''-6y'+6y=e*x sexcx

Simora [160]

From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

$3r^2-6r+6=0\iff r^2-2r+2=0$

which has roots at $r=1\pm i$ . This admits the two fundamental solutions

$y_1=e^x\cos x$
$y_2=e^x\sin x$

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

$y_p=u_1y_1+u_2y_2$

where

$u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$
$u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$

and $W(y_1,y_2)$ is the Wronskian of the fundamental solutions. We have

$W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}$

and so

$u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx$
$u_1=\dfrac13\ln|\cos x|$

$u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx$
$u_2=\dfrac13x$

Therefore the particular solution is

$y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

so that the general solution to the ODE is

$y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

7 0

3 years ago

15 points to answer this question

Mamont248 [21]

it is none since there is no relation

4 0

3 years ago

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What is 1 plus 2 plus 3.... plus 200?

Aneli [31]

Answer:

20100

Step-by-step explanation:

There are 200 numbers in this addition problem. To add this, we can do 1 + 200, 2 + 199, 3 + 198 and so on. All of these pairs have a sum of 201 and since there are 200 / 2 = 100 pairs the answer is 201 * 100 = 20100.

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3 years ago

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Solve the inequality for x<br><br> 20x > 8(4x - 5) - 20

UNO [17]

Hi there! I can help you with this! First, let's combine like terms and do everything for the right side of the problem. When you do the distributive property, you get 32x - 40. Combine like terms and you'll get 32x - 60. Now, the inequality is 20x = 32x - 60. First, let's subtract 32x from both sides to get the integer by itself. When you do that, you get -12x = -60. Now, divide each side by -12 to isolate the "x". -60/-12 is 5. Let's plug it in. 20 * 5 is 100. 32 * 5 is 160. 160 - 60 is 100. 100 = 100. There. x = 5.

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C is the hypotenuse of the right triangle ABC with sides a,b,c

CaHeK987 [17]

Yes C is the hypotenuse

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3 years ago