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Elden [556K]
3 years ago
6

The scatterplot shows the ages and finishing times of seven men who ran a charity 5K run. Use the labeled points to create a lin

ear model that predicts the race time (y) of a man of any age (x). Which equation represents this linear model?
y=o.47x+7.72
y=0.47x+29.15
y=2.146x-27.57
y=2.146x-2.07

Mathematics
2 answers:
sasho [114]3 years ago
7 0

Answer:

A

Step-by-step explanation:

E2020

Alika [10]3 years ago
3 0

Answer:

0.47x + 7.72

Step-by-step explanation:

We have to create a Linear model using the given two points on the graph. The two points are: (21, 17.5) and (43, 2.75)

The general equation of the line in slope intercept form is

y = mx + c

where m is the slope and c is the y-intercept.

Calculating the slope:

slope=m=\frac{\textrm{Difference of y coordinates}}{\textrm{Difference of x coordinates}} \\\\ slope=m=\frac{27.75-17.5}{43-21}\\\\m=0.47

Using the value of m in above equation we get:

y = 0.47x + c

Calculating the y-intercept:

Using any of the given points we can calculate the value of c. Using the point (21, 17.5) in the above equation, we get:

17.5 = 0.47(21) + c

c = 17.5 - 0.47(21)

c = 7.63

Therefore, the equation is:

y = 0.47x + 7.63

Hence option a is the correct answer. The slight change in the value of "c" is because of rounding the value of m to 2 decimal places.

So from the given options, the correct answers is:

y = 0.47x + 7.72

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Leya [2.2K]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
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Shkiper50 [21]

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ivolga24 [154]
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for the second term, starts at 0, and every element it goes up by 1, till it gets to the highest

now, to get the coefficient, they way I get it, is "the product of the current coefficient and the exponent of the first term, divided by the exponent of the second term plus 1"

notice the first coefficient is always 1

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how did we get 10 for the fourth element?  well, 10*2/4


\bf (2x-3y)^4\implies &#10;\begin{array}{llll}&#10;term&coefficient&value\\&#10;-----&-----&-----\\&#10;1&&(2x)^4(-3y)^0\\&#10;2&+4&(2x)^3(-3y)^1\\&#10;3&+6&(2x)^2(-3y)^2\\&#10;4&+4&(2x)^1(-3y)^3\\&#10;5&+1&(2x)^0(-3y)^4&#10;\end{array}


\bf (3a+4b)^8\implies &#10;\begin{array}{llll}&#10;term&coefficient&value\\&#10;-----&-----&-----\\&#10;1&&(3a)^8(+4b)^0\\&#10;2&+8&(3a)^7(+4b)^1\\&#10;3&+28&(3a)^6(+4b)^2\\&#10;4&+56&(3a)^5(+4b)^3\\&#10;5&+70&(3a)^4(+4b)^4\\&#10;6&+56&(3a)^3(+4b)^5\\&#10;7&+28&(3a)^2(+4b)^6\\&#10;8&+8&(3a)^1(+4b)^7\\&#10;9&+1&(3a)^0(+4b)^8&#10;\end{array}

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7 0
3 years ago
Read 2 more answers
Solve the following equation: 7x - 8 = 3x + 12
Paul [167]
X=5
7(5)-8=35-8=27
3(5)+12=15+12=27
3 0
2 years ago
Arithmetic and Geometric Sequences (Context)
V125BC [204]

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r is the annual interest rate in decimal form

n is the number of times it is coupounded per year

t is the number of years

A = 1800 ( 1+ .0375/1) ^ (1*6)

A = 1800 ( 1.0375)^6

A = 2244.92138

Rounding to the nearest cent

A = 2244.92

7 0
1 year ago
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