Answer: 0.0930
Step-by-step explanation:
As per given , we have
H0: μcoffee = 6
Ha: μcoffee < 6
She finds z = −1.68 with one-sided P-value P = 0.0465.
The P-value for two-tailed test is calculated by :

For z= -1.68 , we have

![=2(1-P(z\leq1.68))\ \ [\because\ P(Z>z)=1-P(Z\leq z)]](https://tex.z-dn.net/?f=%3D2%281-P%28z%5Cleq1.68%29%29%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%3Ez%29%3D1-P%28Z%5Cleq%20z%29%5D)
Hence, the correct two-sided P-value for z = −1.68 is 0.0930 .
Answer:

Step-by-step explanation:
<h3>Fraction division:</h3>

Use KCF method.
- Keep the first fraction.
- Change division to multiplication
- Flip the second fraction.


A: .44 (not repeating)
b: also .444 (repeating)
c: .41666666667 (repeating, I think)
d: .875 (not repeating)
because 4x+20y=-36,so ( 4x+20y)/2=2x+10y=-18
(2x+10y)-(2x+5y)=-18-18
5y=-36
then y=-7.2
because 2x=18-5y
so x=(18-5y)/2=(18-5*(-7.2))/2=27
Answer:
the answer might be the 3 option if not then 1
Step-by-step explanation:
hope this helps and tell me if im wrong:)