Answer:
The area is multiplied by 4
Step-by-step explanation:
4x4=16 (area 1)
4(x2)x4(x2)=64 (area 2 (with the measurements doubled)
64/16=4
Answer:
the answer is 0
Step-by-step explanation:
(1/3)(21)-1-(1/2)(12)
The first thing you do is that you multiply 1/3 times 21/1 which equal 7 then you multiply 1/2 times 12/1 which that equal 6 then you solve 7-1-6 and you get 6-6 which equal 0 i hope this help you and i hope you have a goood day.
<em>The question is not clearly readable, but I'm assuming the expression which makes more sense, so you can have a clue</em>
Answer:
![i^{97}-i=0](https://tex.z-dn.net/?f=i%5E%7B97%7D-i%3D0)
Step-by-step explanation:
<u>Powers of The Imaginary Unit</u>
The imaginary unit i is defined as
The first powers of i are
![i^0=1](https://tex.z-dn.net/?f=i%5E0%3D1)
![i^1=i](https://tex.z-dn.net/?f=i%5E1%3Di)
![i^2=(\sqrt{-1})^2=-1](https://tex.z-dn.net/?f=i%5E2%3D%28%5Csqrt%7B-1%7D%29%5E2%3D-1)
![i^3=i.i^2=-i](https://tex.z-dn.net/?f=i%5E3%3Di.i%5E2%3D-i)
![i^4=i^2.i^2=1](https://tex.z-dn.net/?f=i%5E4%3Di%5E2.i%5E2%3D1)
And so on the cycle repeats every four numbers. To find the value of
we can find the remainder of 96/4=0. So ![i^{96}=i^0=1](https://tex.z-dn.net/?f=i%5E%7B96%7D%3Di%5E0%3D1)
The given expression is
![i^{97}-i](https://tex.z-dn.net/?f=i%5E%7B97%7D-i)
Factoring
![i(i^{96}-1)](https://tex.z-dn.net/?f=i%28i%5E%7B96%7D-1%29)
Since ![i^{96}=1](https://tex.z-dn.net/?f=i%5E%7B96%7D%3D1)
![=i(1-1)=0](https://tex.z-dn.net/?f=%3Di%281-1%29%3D0)
The required value is 0
The lowest common denominator is 21