Answer:
Step-by-step explanation:
y = x - 1/4
x = 1/4 Put this value in for x
y = 1/4 - 1/4
y = 0
x = 13/4
y = 13/4 - 1/4 The denominators remain the same The numerators are subtracted.
y = (13 - 1)/4
y = 12/4
y = 3
If x is to = 2 then it must be changed so it's denominator is 4
2 = 8/4
y= 8/4 - 1/4
y = 7/4 or 1.75 or 1 3/4
Answer:
(1)Base Area= 81 square yards.
(2)
-
6 ft long and 8 ft wide
- 24 ft long and 2 ft wide
(3)Height=12 Units
Step-by-step explanation:
<u>Question 1</u>
Volume of the rectangular prism=2,592 cubic yards.
Height of the rectangular prism=32 yards
Volume of a rectangular prism =lbh (where lb is the Base Area)
Therefore:
lbh=2592
32lb=2592
lb=2592/32=81
Base Area= 81 square yards.
<u>Question 2</u>
Volume of the rectangular prism=432 cubic feet.
Height of the rectangular prism=9 feet
Volume of a rectangular prism =lbh (where lb is the Base Area)
Therefore:
lbh=432
9lb=432
lb=432/9=48
Base Area= 48 square yards.
Any dimension whose product is 48 is a possible choice.
They are:
- 3 ft long and 16 ft wide
-
6 ft long and 8 ft wide
- 24 ft long and 2 ft wide
<u>Question 3</u>
<u />
Volume of the rectangular prism=960 cubic units.
Base Area of the rectangular prism, lb=80 Square Units
Volume of a rectangular prism =lbh (where lb is the Base Area)
Therefore:
lbh=960
80h=960
h=960/80=12
Height= 12 units.
Answer:
#2
It is assumed the base of the prism is a square wit side of 5 cm.
<u>The volume is:</u>
<u>The base is:</u>
<u>Find h:</u>
answer
10
step-by-step explanation
the equation given is sin(x) = cos(y) with x = 2k + 3 and y = 6k + 7
substitute in 2k+ 3 for x in sin(x) and substitute in 6k + 7 for y in cos(y)
sin(x) = cos(y)
sin(2k + 3) = cos(6k + 7)
we know that sin(x) = cos(90 -x)
sin(2k + 3)
= cos(90 - (2k + 3) )
= cos(90 - 2k - 3)
= cos(87 - 2k)
substitute this into the equation sin(2k + 3) = cos(6k + 7)
sin(2k + 3) = cos(6k + 7)
cos(87 - 2k) = cos(6k + 7)
87 - 2k = 6k +7
80 = 8k
k = 10
Answer:
(2,-1)
Step-by-step explanation:
If you plug each answer into the equation, (2,-1) is the only answer that makes the equation true. Hope this helps!