In Brenna's rate of speed, 75 MPH, what is the second term of the rate (ratio)?

Mathematics

1 answer:

tatyana61 [14]3 years ago

8 0

Answer: im doing this for points

Step-by-step explanation ok

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The answers to the empty boxes

labwork [276]

In order, for row 6 it is yes, no, no, no yes, yes, no, no, no, yes, yes, no, yes
For row 9 it is all no's
For row 10, it is yes, no, no, no, yes, yes, no, no, no, no, no, yes, yes

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3 years ago

Help with the FIREWORKS question!

liubo4ka [24]

I think the answer is 0.25 seconds later
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3 years ago

Which equation correctly represents the distance between −15.1 and −3.9 on a number line?

Korvikt [17]

Here what we observe

-3.9>-15.1

So as we know about subtracting lowest number is subtracted from highest no

So here

$\\ \tt\longmapsto -3.9-(-15.1)=|-11.2|=11.2$

Distance must be positive

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3 years ago

Roxanne has already jarred 10 liters of jam and will jar an additional 3 liters of jam every

Angelina_Jolie [31]

Answer:

My logic:

so she jars 10 on the first day (that is 1 day) and she wants to jar 16. so if you subtract 10 from 16 you get 6. Now we know she wants to jar 6 more, and if she does 3 every day then you would divide 6 by 3 and get 2. 2+1 is 3, so 3 days. (if you cant chose 3 chose 2 because your teacher might not want yo to count the first day)

Hope this helped!

6 0

3 years ago

A football is kicked from the ground and follows the graph of the function y = –t2 + 3t, where y represents height and t represe

vesna_86 [32]

Answer:

The height of the objects are the same after 2 seconds.

Step-by-step explanation:

In order to calculate at which time both objects have the same height we need to find the value of t that makes both equations equal. Therefore:

$-t^2 + 3t = -t + 4\\t^2 - 3t - t + 4 = 0\\t^2 - 4t + 4 = 0\\t_{1,2} = \frac{-(-4) \pm \sqrt{(-4)^2 - 4*1*4}}{2*1} = \frac{4 \pm \sqrt{16 - 16}}{2}\\t_{1,2} = \frac{4}{2} = 2$

The height of the objects are the same after 2 seconds.

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3 years ago