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Zepler [3.9K]
3 years ago
13

Tarin organized this table to determine the number of adults a and children attending a fundraiser based on the total number of

people attending and the total amount of money raised if $5,860 is raised which statements are true check all that apply ​
Mathematics
2 answers:
GarryVolchara [31]3 years ago
6 0

Answer:

I don't see any answer choices.

I am Lyosha [343]3 years ago
4 0

Answer:

A B E  Got the question right

Step-by-step explanation:

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50 points i need to know how to plot these
svetlana [45]

x is time and y is pencils that you have

'starts with 90' so at x=0, plot y=90

'gives away 15 every hour' so for every 1 hour, move 15 down on y

so at x=1, do 90-15=75 pencils

at x=2, do 75-15=60 pencils

etc

until you get to

x=6, do 15-15=0 pencils then stop because you can't give away 15 pencils when you have 0

see attachment for plot

I don't know how your segment tool works so you do it

if it draws a line, you only need 2 points, just do when x=0, y=90 and when x=6, y=0

5 0
2 years ago
A random sample of 12 recent college graduates reported an average starting salary of $54,000 with a standard deviation of $6,00
Marianna [84]

Answer: a.) $50188 to $57812

Step-by-step explanation: <u>Confidence</u> <u>Interval</u> (CI) is an interval of values in which we are confident the true mean is in.

The interval is calculated as

x ± z\frac{s}{\sqrt{n} }

a. For a 95% CI, z-value is 1.96.

Solving:

54,000 ± 1.96.\frac{6000}{\sqrt{12} }

54,000 ± 1.96\frac{6000}{3.464}

54,000 ± 1.96*1732.102

54,000 ± 3395

This means the interval is

50605 < μ < 57395

<u>With a 95% confidence interval, the mean starting salary of college graduates is between 50605 and 57395 or </u><u>from 50188 to 57812$.</u>

<u />

b. The mean starting salary for college students in 2017 is $50,516, which is in the confidence interval. Therefore, since we 95% sure the real mean is between 50188 and 57812, there was no significant change since 2017.

4 0
2 years ago
If someone could help me figure out #7 ASAP I’d really appreciate it
IceJOKER [234]

Answer: Angle N

Explanation:

For triangle ABC, we refer to the middle angle, Angle B.

For triangle MNP, we refer to its middle angle, Angle N.

Good luck!

8 0
2 years ago
The passing yards for the top 5 quarterbacks in the country are 3,832, 3,779, 3,655, 3,642, and 3,579. Find the variance and sta
Leviafan [203]

First get the average passing yards:

(3,832 + 3,779 + 3,655 + 3,642 + 3,579) / 5 = 3,697.4

Now get the squared residuals for each quarterback's passing yards. That is, compute the difference between each data and the average, then square the result. For example,

(3,832 - 3,697.4)^2 = 134.6^2 = 18,117.2

For the others, you should get squared residuals of

6,658.56

1,797.76

3,069.16

14,018.6

Take the sum of the squared residuals, then - since this is a sample, and not a population of all quarterbacks - divide the sum by 5 - 1 = 4 to get the variance:

(18,117.2 + 6,658.56 + 1,797.76 + 3,069.16 + 14,018.6)/4 = 10,915.3

The standard deviation is just the square root of the variance:

√(10,915.3) ≈ 104.48

5 0
3 years ago
Read 2 more answers
Please help ill give brain
Rasek [7]

Answer:

23 r1

Step-by-step explanation:

                 

                                    23 R 1

                            28/653

                                 -56

                                      93            bring down three

                                      92

                                       =1 which is remainder

28*2=56

28*3=92

6 0
3 years ago
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