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Tpy6a [65]
3 years ago
12

Elias and Niko are polishing the silver at the heritage museum.Elias could polish all the silver himself in 40 minutes.That task

would take Niko 50 minutes to complete alone.Whick table is filled in correctly and could be used to determine how long it would take Elias and Niko polished te silver together?
Mathematics
2 answers:
irina1246 [14]3 years ago
6 0

Let x be the time it takes Elias and Niko to polish the silver working together. If Elias works alone, he could polish all the silver himself in 40 minutes. Then, in 1 minute, he will make \frac{1}{40} of the total work. If the same analysis is applied Niko, in 1 minute, will make \frac{1}{50} of the total work.


Working together Elias and Niko will need x minutes to make all the work. Then, in 1 minute, they will make \frac{1}{x} of the total work.  So, the fraction of the total work they make in 1 minute is given by this equation:

\frac{1}{x}=\frac{1}{40}+\frac{1}{50} \\ \\ \frac{1}{x}=\frac{50+40}{2000} \\ \\ x=\frac{2000}{90} \\ \\ \boxed{x=22.22 minutes}

wel3 years ago
4 0
We let x be the number of hours both could the job together.
The fraction of the job done by Elias is
x/40

The fraction of the job done by Niko is
x/50

Together they would be able to finish the job (one job)

x/40 + x/50 = 1
x = 1 / (1/40 + 1/50)
x = 22.22 minutes
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Min =120, Max= 150

The first quartile can be calculated with this data:

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The median is the value in the 6th position from the dataset ordered and we got:

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The third quartile can be calculated with this data:

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The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

Step-by-step explanation:

We have the following data given:

130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150

If we sort the values on increasing order we got:

120 130 130 130 130 135 140 140 143 144 150

The minimum and maximum are:

Min =120, Max= 150

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

Q_1 = \frac{140+120}{2}=130

The median is the value in the 6th position from the dataset ordered and we got:

Median= 135

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

Q_3 = \frac{140+143}{2}=141.5

The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

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Answer:

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Step-by-step explanation:

4 0
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