(x^4)(3x^3-2)(4x^2+5x)
=(3x^7-2x^4)(4x^2+5x)
=12x^9+15x^8-8x^6-10x^5
answer: 12x^9+15x^8-8x^6-10x^5
It is commutative property of multiplication
First, draw and label a rough sketch of an isosceles triangle. Now put in the values of pq=2x+3 and pr=9x-11
You know that the triangle is isosceles, therefore, the sides pq and pr are identical.
Now, make the equations equal to each other to find the value of x.
2x+3=9x-11
3+11=9x-2x
14=7x
14/7=x
2=x
Therefore the value of x=2.
Hope I helped :)