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LuckyWell [14K]
3 years ago
13

The function y=-16x^2+16x+32 represents the height in feet of a firework x seconds after it is launched

Mathematics
1 answer:
Nadya [2.5K]3 years ago
8 0

Answer:

36feet

Step-by-step explanation:

Since we are not asked what to find, we can as well find the maximum height reached by the rocket

At max height, velocity is zero

V = dy/dx = 0

dy/dx = -32x + 16

0 = -32x+16

32x = 16

x = 16/32

x = 0.5s

Get the maximum height

y = -16(0.5)^2+16(0.5) + 32

y = -4+8+32

y = 36feet

Hence the max height reached by the rocket is 36feet

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