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Aleksandr [31]
3 years ago
5

Just out of curiosity, what is (-7)-(+6)?

Mathematics
1 answer:
zimovet [89]3 years ago
5 0
The answer is (-7)-(6)= -1
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Help please <br> Right angle triangle
baherus [9]

Answer:

h ≈ 11.9

Step-by-step explanation:

Since the triangle is right we can use the cosine ratio to find h

cos24° = \frac{adjacent}{hypotenuse} = \frac{h}{13}

Multiply both sides by 13

13 × cos24° = h

⇒ h = 11.9 cm ( to 1 dec. place )

8 0
3 years ago
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Unit 5. 17) Please help. Which solids could have a cross section in the shape shown above?
e-lub [12.9K]

Answer:

I think the correct answers are options 2 and 4.

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3 years ago
Find the slope of this line
Yanka [14]

Answer:

Undefined (DNE)

Step-by-step explanation:

Any vertical line has an undefined slope.

8 0
1 year ago
The graph below shows the cost that Hondo pays for apples. What does the point (0,0) on this graph mean?
timurjin [86]

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(0,0) means that he didn't buy any apples so it doesn't cost anything

Step-by-step explanation:

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3 years ago
An urn contains 8 red chips, 10 green chips, and 2 white chips. A chip is drawn and replaced, and then a second chip is drawn.
Harlamova29_29 [7]

Answer:

(A) 0.04

(B) 0.25

(C) 0.40

Step-by-step explanation:

Let R = drawing a red chips, G = drawing green chips and W = drawing white chips.

Given:

R = 8, G = 10 and W = 2.

Total number of chips = 8 + 10 + 2 = 20

P(R) = \frac{8}{20}=\frac{2}{5}\\P(G)=  \frac{10}{20}=\frac{1}{2}\\P(W)=  \frac{2}{20}=\frac{1}{10}

As the chips are replaced after drawing the probability of selecting the second chip is independent of the probability of selecting the first chip.

(A)

Compute the probability of selecting a white chip on the first and a red on the second as follows:

P(1^{st}\ white\ chip, 2^{nd}\ red\ chip)=P(W)\times P(R)\\=\frac{1}{10}\times \frac{2}{5}\\ =\frac{1}{25} \\=0.04

Thus, the probability of selecting a white chip on the first and a red on the second is 0.04.

(B)

Compute the probability of selecting 2 green chips:

P(2\ Green\ chips)=P(G)\times P(G)\\=\frac{1}{2} \times\frac{1}{2}\\ =\frac{1}{4}\\ =0.25

Thus, the probability of selecting 2 green chips is 0.25.

(C)

Compute the conditional probability of selecting a red chip given the first chip drawn was white as follows:

P(2^{nd}\ red\ chip|1^{st}\ white\ chip)=\frac{P(2^{nd}\ red\ chip\ \cap 1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\=\frac{P(2^{nd}\ red\ chip)P(1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\= P(R)\\=\frac{2}{5}\\=0.40

Thus, the probability of selecting a red chip given the first chip drawn was white is 0.40.

6 0
3 years ago
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