Is the equation like this? x^2 + 25y^2?
If the equation is like that, the answer would be (x-5y)^2 or (x-5y)(x-5y).
how did I get this? Just divide the factors or the get the square root of 25y^2 and it would be 5y. Then just try if it is positive or negative. In this case, it is negative because there is no factor w/ no exponential form. I hopemy answer helped you.
Answer:
(5,-4)
Step-by-step explanation:
If reflected over the x-axis, the quadrilateral would be in the fourth quadrant. N' would be at (1,-1) and P' at (6,-1). To reflect, look at the y-coordinate of the point and turn it to negative. With point Q, it's at (5,4) so we just flip the 4 to -4 and that's our point! (5,-4)
-4x^2 - 8......input (x) = 2
-4(2^2) - 8 =
-4(4) - 8 =
-16 - 8 =
- 24 <==
Answer:
72 m\ p.h.
Step-by-step explanation:
we have 60 minute in one hour
we must divide 60 by 5=12
then 6*12=72!!!
it is very easy
