Answer:
When we have a rational function like:

The domain will be the set of all real numbers, such that the denominator is different than zero.
So the first step is to find the values of x such that the denominator (x^2 + 3) is equal to zero.
Then we need to solve:
x^2 + 3 = 0
x^2 = -3
x = √(-3)
This is the square root of a negative number, then this is a complex number.
This means that there is no real number such that x^2 + 3 is equal to zero, then if x can only be a real number, we will never have the denominator equal to zero, so the domain will be the set of all real numbers.
D: x ∈ R.
b) we want to find two different numbers x such that:
r(x) = 1/4
Then we need to solve:

We can multiply both sides by (x^2 + 3)


Now we can multiply both sides by 4:


Now we only need to solve the quadratic equation:
x^2 + 3 - 4*x - 4 = 0
x^2 - 4*x - 1 = 0
We can use the Bhaskara's formula to solve this, remember that for an equation like:
a*x^2 + b*x + c = 0
the solutions are:

here we have:
a = 1
b = -4
c = -1
Then in this case the solutions are:

x = (4 + 4.47)/2 = 4.235
x = (4 - 4.47)/2 = -0.235
The answer is <span>one halfn − 16
</span>
Let the number be n.
<span>One half of a number is (1/2n)
</span><span>decreased by 16 is (-16)
</span><span>one half of a number decreased by 16 is
1/2n - 16
Or </span><span>one halfn − 16</span>
Answer:
112 m
Step-by-step explanation:
The area (A) of a square is
A = s² ( s is the length of side )
Here A = 784 , then
s² = 784 ( take the square root of both sides )
s =
= 28
Then
perimeter = 4s = 4 × 28 = 112 m
V ,= 4/3 πr³
solve for r
3V/4=r³
so r is the cubed root of 3V/4
Four batches should be the correct answer