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Assoli18 [71]
3 years ago
14

What is the area of this trapezoid?​

Mathematics
2 answers:
Anna [14]3 years ago
7 0
The anser is the second box circle thing
m_a_m_a [10]3 years ago
6 0

answer:

i believe the answer is c

good luck :) hopefully this helps

have a great day !!

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A chef mixed oil and vinegar to make a salad dressing she made enough dressing to fill 6 plastic bottles each bottle has 4/8 cup
Nataly [62]
48 cups because there are 8 cups in a bottle and 8 times 6 is 48
5 0
3 years ago
Solve for x ill give brainlest!!!
butalik [34]

Answer:

x=-9

Step-by-step explanation:

36^{x-3}=1296^{x+3}\\(6^2)^{x-3}=(6^4)^{x+3}\\2(x-3)=4(x+3)\\x-3=2x+6\\x+6=-3\\x=-9

8 0
3 years ago
You read 4 1/2 pages in 12 minutes. at the same rate, how many pages could you read in an hour?​
nignag [31]

Answer:

22.5 pages

Step-by-step explanation:

First divide the page number by the minutes it takes to read them to find pages per minute-

4.5 / 12 = .375

Then take that number and multiply it by the minutes in an hour-

(.375) (60) = 22.5

22.5 pages in one hour.

5 0
3 years ago
Read 2 more answers
what is the slope of a line that is perpendicular to the line that contains points (5,4) and (-7,9). explain please
Luba_88 [7]

Answer:

\frac{12}{5}

Step-by-step explanation:

First find the slope of the line containing points (5,4) and (-7,9).  To find the slope use the formula \frac{y_{2} -y_{1}}{x_{2}-x_{1}}.  Putting those values in, you have

\frac{9-4}{-7-5}

Simplify

\frac{5}{-12}

-\frac{5}{12}

Then, to find the slope of the line perpendicular to that, find the negative reciprocal.  

\frac{12}{5}

3 0
3 years ago
A random sample of 77 fields of durum wheat has a mean yield of 27.427.4 bushels per acre and standard deviation of 5.755.75 bus
xz_007 [3.2K]

Answer:

[ 21.79, 33.0 ]

Step-by-step explanation:

Given:

Sample size, n = 7

Sample mean, μ = 27.4

Standard deviation, σ = 5.75

Confidence level is 99%

also, population is normal i.e normally distributed

Thus,

Confidence interval = μ ± z\frac{\sigma}{\sqrt n}

For confidence level of 99%

z-value = 2.58

Therefore,

Lower limit of Confidence interval = μ - 2.58\times\frac{5.75}{\sqrt{7}}

or

Lower limit of Confidence interval = 27.4 - 2.58\times\frac{5.75}{\sqrt{7}}

or

Lower limit of Confidence interval = 21.79

Upper limit of Confidence interval = μ + 2.58\times\frac{5.75}{\sqrt{7}}

or

Upper limit of Confidence interval = 27.4 + 2.58\times\frac{5.75}{\sqrt{7}}

or

Upper limit of Confidence interval = 33.00

Hence, confidence interval = [ 21.79, 33.0 ]

5 0
3 years ago
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