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Assoli18 [71]
3 years ago
14

What is the area of this trapezoid?​

Mathematics
2 answers:
Anna [14]3 years ago
7 0
The anser is the second box circle thing
m_a_m_a [10]3 years ago
6 0

answer:

i believe the answer is c

good luck :) hopefully this helps

have a great day !!

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It says it in the image please help me
r-ruslan [8.4K]

Answer:

The answer you have selected should be correct.

6 0
2 years ago
Please help, will give 25 points
puteri [66]

Answer:

need to find value of x

Step-by-step explanation:

5 0
3 years ago
3 l = _____ dl<br><br> A. 0.3<br> B. 0.03<br> C. 300<br> D. 30
Andru [333]

Answer: The correct option is D, i.e.,30.

Explanation:

It the given equation we have two units l and dl.

Where l represents the liter and dl represents the deciliter. These are the volume units.

We know that,

1 liter = 10 deciliter

It means,

1 l = 10 dl

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6 0
3 years ago
Which term does not describe a square?
forsale [732]

Answer: a

Step-by-step explanation:

7 0
3 years ago
Evaluate the integral. 3 2 t3i t t − 2 j t sin(πt)k dt
sveta [45]

∫(t = 2 to 3) t^3 dt

= (1/4)t^4 {for t = 2 to 3}

= 65/4.

----

∫(t = 2 to 3) t √(t - 2) dt

= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2

= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du

= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}

= 26/15.

----

For the k-entry, use integration by parts with

u = t, dv = sin(πt) dt

du = 1 dt, v = (-1/π) cos(πt).


So, ∫(t = 2 to 3) t sin(πt) dt

= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt

= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]

= 5/π + 0

= 5/π.

Therefore,

∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.

3 0
3 years ago
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