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UNO [17]
3 years ago
15

Write an expression that represents the sum of x and 8

Mathematics
1 answer:
krok68 [10]3 years ago
6 0

Answer:

x+8

Step-by-step explanation:

we know that

The phrase " the sum of x and 8" is equivalent to adds the number x and the number 8 or sum the number x plus the number 8

so

x+8

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How can Ann group 38 rocks different
Zanzabum
She can put the rocks into,
2 groups of 19
Or one group of 38.
3 0
3 years ago
A number greater than -5
Serggg [28]

Answer:

Hi there!

Your answers are:

1) x> 5

Some numbers that would fit this equation are 6, 7, 8, etc!

2) x<= 30

Some numbers that would fit this are 30, 29, 28, etc!

3) x>= 17

Some numbers that would fit this equation are 17, 18, 19, etc!

4) x>= 90

Some numbers that would fit this are 90, 91, 92, etc!

Hope this helps!

5 0
3 years ago
A recipe uses 2 cups of milk to make 4 servings. If the same amount of milk is used for each serving, how many servings can be m
iren2701 [21]

Answer:

12 servings

Step-by-step explanation:

Please let me know if you want me to write an explanation for my answer :)

7 0
3 years ago
A diagnostic test for a disease is such that it (correctly) detects the disease in 90% of the individuals who actually have the
Ne4ueva [31]

Answer:

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Test positive

Event B: Has the disease

Probability of a positive test:

90% of 3%(has the disease).

1 - 0.9 = 0.1 = 10% of 97%(does not have the disease). So

P(A) = 0.90*0.03 + 0.1*0.97 = 0.124

Intersection of A and B:

Positive test and has the disease, so 90% of 3%

P(A \cap B) = 0.9*0.03 = 0.027

What is the conditional probability that she does, in fact, have the disease

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.027}{0.124} = 0.2177

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

3 0
3 years ago
Give two solutions of the inequality: p ≤ 3
Sonja [21]

Answer:

3,2

Step-by-step explanation:

3 is equal to 3 which can be it and 2 is less than 3

7 0
3 years ago
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