Answer:
The displacement of the spring, as measured from equilibrium, is 0.301 m
Explanation:
Hi there!
Using Hooke´s law, we can calculate the displacement of the spring:
F = -kx
Where:
F = restoring force exerted by the spring.
k = spring constant.
x = displacement of the spring.
The force exerted by the spring can also be calculated using the Newton law:
F = m · a
Where:
F = force.
m = mass of the object.
a = acceleration.
Then, combining both laws:
F = -k · x = m · a
-k · x = m · a
-339 N/m · x = 10.0 kg · 10.2 m/s²
x = 10.0 kg · 10.2 m/s² / -339 N/m
x = -0.301 m
The displacement of the spring, as measured from equilibrium, is 0.301 m
Argon - Noble gas
Group - 18
Period - 3
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Answer:
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Explanation:
Your book has applied the chain rule to produce:
dv/dt = dv/dx * dx/dt
Now, we can get dv/dx by:
1) Differentiate
x = vt, with respect to v.
dx/dv = t
Now, if we take the inverse of this, we can obtain dv/dx
dv/dx = 1/t
This is also proven by the fact that dv/dx is the change in velocity and if you multiply it by dv/dx, which is equivalent to dividing by the change in time, as we just proved, then you obtain acceleration.
Answer: The answer is 19,600 newtons.
Explanation: