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Aleonysh [2.5K]
2 years ago
8

1. Two-point charges, QA = +8 μC and QB = -5 μC, are separated by a distance r = 10 cm. What is the magnitude and direction of t

he electric force? The constant k = 9 x 109 N-m2/C2
Solution:
Physics
1 answer:
densk [106]2 years ago
3 0

Answer:

F = 36 N

Explanation:

Given that,

Charge, q₁ = +8 μC

Charge, q₂ = -5 μC

The distance between the charges, r = 10 cm = 0.1 m

We need to find the magnitude of the electrostatic force. The formula for the electrostatic force is given by :

F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times8\times 10^{-6}\times 5\times 10^{-6}}{(0.1)^2}\\F=36\ N

So, the magnitude of the electrostatic force is 36 N.

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Which is the correctly balanced equation for the reaction of rust, Fe2O3, and hydrochloric acid, HCl?
Mariana [72]

Answer: Option (c) is correct answer.

Explanation:

The given reaction equation is as follows.

          Fe_{2}O_{3} + HCl \rightarrow FeCl_{3} + H_{2}O

The number of atoms on reactant side are as follows.

  • Fe = 2
  • O = 3
  • H = 1
  • Cl = 1

The number of atoms on product side are as follows.

  • Fe = 1
  • O = 1
  • H = 2
  • Cl = 3

Therefore, in order to balance the equation we will balance the number of atoms in both reactant and product side.

Since number of Fe atoms in reactant side is 2, therefore, multiply FeCl_{3} by 2 in the product side.

Number of O atoms in reactant side is 3, therefore, multiply H_{2}O by 3 in the product side.

Now, the number of H atoms on product side is 6, therefore, multiply HCl by 6 in the reactant side.

The number of chlorine atoms on both reactant and product side equals 6.

Thus, the equation will become as follows.

             Fe_{2}O_{3} + 6HCl \rightarrow 2FeCl_{3} + 3H_{2}O

Hence, the equation is balanced.

5 0
3 years ago
Read 2 more answers
In countries where there is very hot and very cold weather, should the gaps between the lengths of railway track be wider or nar
kipiarov [429]
They should be bigger as if it is hot the tracks will expand as it is made of metal and then there is more room for it to expand or contract
5 0
3 years ago
2
ella [17]
C : I did this already
6 0
2 years ago
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An automobile battery has an emf of 12.6 V and an internal resistance of 0.0600 . The headlights together present equivalent res
murzikaleks [220]

Answer:

(a) V=11.86\ V

(b) V=9.76\ V

Explanation:

<u>Electric Circuits</u>

Suppose we have a resistive-only electric circuit. The relation between the current I and the voltage V in a resistance R is given by the Ohm's law:

V=R.I

(a) The electromagnetic force of the battery is \varepsilon =12.6\ V and its internal resistance is R_i=0.06\ \Omega. Knowing the equivalent resistance of the headlights is R_e=5.2\ \Omega, we can compute the current of the circuit by using the Kirchhoffs Voltage Law or KVL:

\varepsilon=i.R_i+i.R_e=i.(R_i+R_e)

Solving for i

\displaystyle i=\frac{\varepsilon}{ R_i+R_e}=\frac{12}{0.06+5.2}=2.28\ A

i=2.28\ A

The potential difference across the headlight  bulbs is

V=\varepsilon  -i.R_i=12\ V-2.28\ A\cdot 0.06\ \Omega=11.86\ V

V=11.86\ V

(b) If the starter motor is operated, taking an additional 35 Amp from the battery, then the total load current is 2.28 A + 35 A = 37.28 A. Thus the output voltage of the battery, that is the voltage that the bulbs have is

V=\varepsilon  -i.R_i=12\ V-37.28\ A\cdot 0.06\ \Omega=9.76\ V

5 0
3 years ago
What measures the amount of energy in a wave
yawa3891 [41]

Answer:

amplitude of the wave

................

5 0
3 years ago
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