The best answer would be the second option B) because that is NOT part of the Kinetic Molecular Theory.
The spring will come to rest 4.9 m below the natural length
Explanation:
The mass-spring system will come to rest when the restoring force on the spring (pulling upward) balances the weight of the mass (pulling downward). Mathematically, this can be written as

where
k is the spring constant
x is the elongation of the spring
m is the mass
g is the acceleration of gravity
In this problem, we have:
is the mass
is the acceleration of gravity
is the spring constant
Solving the equation for x,

Therefore, the spring will come to rest 4.9 m below the natural length.
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<span>The magnitude of the gravitational force between two bodies is the product of their masses divided by the square of the distance between them. So we have F = M1*M2 / r^2. M1 = 7.503 * 10e24 and M2 = 2.703 * 10e22 and r= 2.803 * 10e8; r^2 = 5.606 *10e16. So we have 7.503 *2.703 *10^(24+22) = 20.280 * 10^(46). Then we divide our answer by 5.606 * 10e16 which is the distance ; then we have 3.6175 * 10 e (46- 16) = 3.6175 * 10e30.
To find the acceleration we use Newton's second law F = ma. F is 3.6175 * 10e30 and M is 7.503 * 10e24 so a = F/M and then we have 3.6175/7.503 * 10e (30-24) = 0.48 * 10e6.
Similarly for moon, we have a = 3.6715/2.703 * 10e(30-22). = 1.358 * 10e8</span>
Answer:
The height reached by the dart in the second shot is (4 H).
Explanation:
It is given that, a spring-loaded toy dart gun is shot to a height h. In this case, all the potential energy stored in the spring is converted to potential gravitational energy at the maximum height.
........(1)
At the second shot, the spring is compressed twice as far before firing. x' = 2x

.........(2)
h is the height reached by the dart in the second shot.
Dividing equation (1) and (2) as:

h = 4H
So, the height reached by the dart in the second shot is (4 H). Hence, this is the required solution.