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3 years ago

An astronaut has a weight of 2000 kg elephant

Physics

1 answer:

Snowcat [4.5K]3 years ago

6 0

Answer: The answer is 19,600 newtons.

Explanation:

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The thickest and strongest chamber in the human heart is the left ventricle, responsible during systole for pumping oxygenated b

Bess [88]

Answer:

(a). The blood travel during this acceleration is 0.0231 m.

(b). The time for the blood to reach its peak speed is 0.0459 sec.

Explanation:

Given that,

Acceleration = 22.0 m/s²

Speed = 1.01 m/s

(a). We need to calculate the distance

Using equation of motion

$v^2=u^2+2as$

Where, v = final speed

u = initial speed

a = acceleration

s = distance

Put the value into the formula

$(1.01)^2=0+2\times22.0\times s$

$s=\dfrac{(1.01)^2}{2\times22.0}$

$s=0.0231\ m$

(b). We need to calculate the time

Using equation of motion

$v =u+at$

Put the value into the formula

$1.01=0+22t$

$t=\dfrac{1.01}{22}$

$t=0.0459\ sec$

Hence, (a). The blood travel during this acceleration is 0.0231 m.

(b). The time for the blood to reach its peak speed is 0.0459 sec.

4 0

3 years ago

Jaime lifts a package weighing 75N. if she lifts it 1.2 m, what work has she done

9966 [12]

Answer:
90 J
Explanation:
W=fd
W=(75)(1.2)
W= 90 J

6 0

3 years ago

Using newtons law How much force is accelerated a 66kg skier 2m/s2

Evgen [1.6K]

Answer:

SUPONIENDO QUE NO HAY FRICCIÓN

Explanation:

F = 66 kg( $2 m/s^{2}$ ) = 132 N

8 0

3 years ago

A solid sphere of brass (bulk modulus of 14.0 ✕ 1010 N/m2) with a diameter of 2.20 m is thrown into the ocean. By how much does

astra-53 [7]

Answer:

Diameter decreases by the diameter of 0.0312 m.

Explanation:

Given that,

Bulk modulus = 14.0 × 10¹⁰ N/m²

Diameter d = 2.20 m

Depth = 2.40 km

Pressure = ρ g h = 1030 × 9.81 × 2.4 × 1000

= 24.25 × 10⁶ N/m²

Volume = $\dfrac{4}{3} \pi r^3$

$\dfrac{\Delta V}{V}=\dfrac{(\Delta r)^3}{r^3}$

Bulk modulus is equal to

$B = -\dfrac{\Delta P}{\dfrac{\Delta V}{V} }$

now

$B = -\dfrac{24.25 \times 10^6}{\dfrac{(\Delta r)^3}{r^3} }$

$B = -\dfrac{24.25 \times 10^6}{\dfrac{(\Delta r)^3}{1.1^3} }$

$(\Delta r)^3 = \dfrac{24.25 \times 10^6 \times 1.1^3}{14.0 \times 10^{10}}$

Δ r = -0.0156 m

change in diameter

Δ d = -2 × 0.0156

Δ d = -0.0312 m

Diameter decreases by the diameter of 0.0312 m.

7 0

3 years ago

A round pipe of varying diameter carries petroleum from a wellhead to a refinery. At the wellhead, the pipe's diameter is 50.9 c

seraphim [82]

Answer:

Flow rate 2.34 m3/s

Diameter 0.754 m

Explanation:

Assuming steady flow, the volume flow rate along the pipe will always be constant, and equals to the product of flow speed and cross-section area.

The area at the well head is

$A = \pi r_w^2 = \pi (0.509/2)^2 = 0.203 m^2$

So the volume flow rate along the pipe is

$\dot{V} = Av = 0.203 * 11.5 = 2.34 m^3/s$

We can use the similar logic to find the cross-section area at the refinery

$A_r = \dot{V}/v_r = 2.34 / 5.25 = 0.446 m^2$

The radius of the pipe at the refinery is:

$A_r = \pi r^2$

$r^2 =A_r/\pi = 0.446/\pi = 0.141$

$r = \sqrt{0.141} = 0.377m$

So the diameter is twice the radius = 0.38*2 = 0.754m

6 0

3 years ago