Question

a projectile is launched from level ground with an initial speed v0 at an angle θ with the horizontal. if air resistance is negligible, how long will the projectile remain in the air?

Answer 1

The time of flight of the launched particle will be 2v₀ sinθ / g.

What is kinematics?

The study of motion without considering the mass and the cause of the motion.

A projectile is launched from level ground with an initial speed v₀ at an angle θ with the horizontal. If air resistance is negligible.

Then the time of flight of the launched particle will be given as,

Determine how long it requires the projectile to reach its highest point in order to calculate the flight duration. Just twice as long as the maximum altitude is the travel time.

$\rm v_y = v_{o_y} + a_y t$

At maximum height, $\rm v_y = 0$.

The time to reach maximum height is given as

$\rm t_{1/2} = - \dfrac{v_{o_y} }{ a_y}$

The time of flight is given as,

$\rm t = 2 \times t_{1/2} = - \dfrac{2v_{o_y}}{ a_y}$

Substituting in $\rm v_{o_y} = v_o \ \sin(\theta ) \ and \ a_y = -g$, then we have

The time of flight of the launched particle will be 2v₀ sinθ / g.

More about the kinematics link is given below.

brainly.com/question/7590442

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