2 years ago

Please help me this is my test I'm stuck on this one

1 answer:

8 0

Ok pretty sure the probability of a 5 is 1/5

The probability of a # greater than 3 is 2/5

And the probability of a 2 or 5 is 2/5

(1/5 is 20% and 2/5 is 40% if you need those)

You might be interested in

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER

Yakvenalex [24]

Answer:

The surface area of ball is 400π sq.cm

6 0

2 years ago

Given the functions, f(x)=x^3+2 and g(x)=x-9, perform the indicated operation. When applicable, state the domain restriction. (f

tiny-mole [99]

The domain of (f/g)(x) considers the domains of g(x) and f(x) and makes sure that g(x)≠0

because (f/g)(x)=f(x)/g(x)
and division by 0 is not allowed

the domains of f(x) and g(x) are all real numbers
now find what make g(x)=0
0=x-9
9=x

9 is restricted from the domain
domain is all real numbers except 9

so
$(\frac{f}{g})(x)=\frac{f(x)}{g(x)}=$
$\frac{x^3+2}{x-9}$
the domain is all real numbers except for 9

7 0

3 years ago

∆ABC m∠B = 90° AB = 4 BC = 3<br> Find AC

lutik1710 [3]

Step-by-step explanation:

In ∆ABC, m∠B = 90°

Therefore ∆ABC is a right angled triangle with sides AB = 4 & BC = 3. AC is the hypotenuse.

Hence, by Pythagoras theorem:

$AC^2 = AB^2 +BC^2 \\ \\ \therefore \: AC = \sqrt{AB^2 +BC^2 } \\ = \sqrt{ {4}^{2} + {3}^{2} } \\ = \sqrt{16 + 9} \\ = \sqrt{25} \\ = 5 \\ \\ \huge \red{ \boxed{ \therefore \: AC = 5 \: units}}$