The total cost would be:
$20 = two people- 2*20=40$
20 = guest
20*20=
400 would be the cost
Answer:
C) Octagon
Step-by-step explanation:
Answer:
Step-by-step explanation:
The wording on this is not the best. It sounds like the 1 zero has even multiplicity (that's because of where the modifier is). On top of that it has an odd power. You could try this. y =x*(x^2+1)^2
The problem is not with the power. It gives x^5. The problem is with the multiplicity of the one place where it crosses. (X^2 + 1) does factor, but it gives a complex root. I'm not sure that's allowed. However, it is the best I can do.
Answer:
ewfyeet
Step-by-step explanation:
Answer: 1) (-∞, -6) U (-3, ∞)
2) (-∞, -4) U (2, ∞)
3) (-∞, -3) U (8, ∞)
<u>Step-by-step explanation:</u>
Find the zeros. Since the a-value is positive, the curve will be positive to the left of the leftmost zero and to the right of the rightmost zero. + - +
←---|----|--→
1) y = x² + 9x + 18
y = (x + 3)(x + 6)
0 = (x + 3)(x + 6)
0 = x + 3 0 = x + 6 + -- +
x = -3 x = -6 ←------|-----------|--------→
-6 -3
Positive Interval: (-∞, -6) U (-3, ∞)
2) y = x² + 2x - 8
y = (x + 4)(x - 2)
0 = (x + 4)(x - 2)
0 = x + 4 0 = x - 2 + -- +
x = -4 x = 2 ←------|-----------|--------→
-4 2
Positive Interval: (-∞, -4) U (2, ∞)
3) y = x² - 5x - 24
y = (x + 3)(x - 8)
0 = (x + 3)(x - 8)
0 = x + 3 0 = x - 8 + -- +
x = -3 x = 8 ←------|-----------|--------→
-3 8
Positive Interval: (-∞, -3) U (8, ∞)
