Answer:
Given the number of platters =5
A. Hence, the number of recording surface =10
B. number of read-write heads =10
C. Number of arms holding the read-write heads = 10
Explanation:
We know that number of recording surface = 2 *( number of platters)
= 2*5=10
And the number of read-write heads = number of recording surface= 10
Also, number of arms holding the read-write head = one for each read-write head= 10
And hence, the above answer.
Based on the declaration "int b[ 2 ][ 2 ] = { { 1 }, { 3 , 4 } };" given, the value of b[ 1 ][ 0 ] is equal to 3.
<h3>What is Python?</h3>
Python can be defined as a high-level programming language that is designed and developed to build websites and software applications, especially through the use of dynamic commands (semantics), declarations, functions, and data structures.
<h3>What is an int?</h3>
Int is an abbreviation for an integer and it can be defined as a whole number that may either be positive, negative, or zero.
Based on the declaration "int b[ 2 ][ 2 ] = { { 1 }, { 3 , 4 } };" given, we can infer and logically deduce that the value of b[ 1 ][ 0 ] is equal to 3.
Read more on Python integers here: brainly.com/question/18761825
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Answer: D.) All of the above. (happy to help)
Explanation: A.)
problem solving
B.)
expertise
C.)
content
D.)
all of the above
Answer:
The wireless adapter to use is the Wireless USB 2.0 Extender
Explanation:
The Wireless USB 2.0 Extender is a USB component that enables a computer to connect to and communicate with other computers on a network, or even to connect to the internet.
It uses an IEEE 802.11g radio platform and communicates within a radio frequency range of 2.4GHz.
Therefore, in cases where a notebook computer does not have a built-in wireless LAN card or PC card interface, you can use the Wireless USB 2.0 Extender as the best solution to that problem.
Answer:
0.8488
Explanation:
Let E =error found by test 1
Let F=error found by test 2
Let G=error found by test 3
Let H=error found by test 4
Let I= error found by test 5
Given P(E)=0.1, P(F)=0.2, P(G)=0.3, P (H)= 0.4, P (I)=0.5
therefore P(notE)=0.9, P(notF)=0.8, P(notG)=0.7, P(not H)=0.6, P (notI)=0.5
Tests are independent P(not E & not F ¬ G & not H & not I=P(notE)*P(notF)*P(notG)*P (notH)*P (not I) =0.9*0.8*0.7*0.6*0.5 =0.1512
P(found by at least one test)= 1- P(not found by any test)=1-P(not E& not F & not G & not H & not I ) = 1-0.1512 = 0.8488
