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Levart [38]
3 years ago
6

Rearrange x= v+5 to make v the subject.

Mathematics
2 answers:
zimovet [89]3 years ago
7 0
X = v + 5

x - 5 = v

v = x - 5
Darina [25.2K]3 years ago
3 0

x = v + 5

x - 5 = v + 5 - 5

x - 5 = v

v = x - 5

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Use integers that are that are closest to the number in the middle. < - v119
Leni [432]

Answer:

  -11 and -10

Step-by-step explanation:

  -11² = -121

  -(√119)² = -119

  -10² = -100

_____

  -√119 is between -11 and -10

3 0
3 years ago
Prove that the lengths of the diagonals of an isosceles trapezoid are equal
SOVA2 [1]
AD || BC 
<span>• AB = CD </span>
<span>• ∠BAD = ∠CDA (a given condition ∵ ABCD is an isosceles trapezium) </span>

<span>The diagonals AC and BD create two ∆'s: ∆ABD, and ∆ACD </span>

<span>The two ∆'s are congruent (SAS).  </span>
 
<span>(S): AB = CD </span>
<span>(A): ∠BAD = ∠CDA 
</span><span>(S): AD = DA (common side) </span>
<span>
The corresponding sides of the two ∆'s, BD and AC, are also congruent. </span>
<span>(the two diagonals of the trapezium/trapezoid) 
</span>
6 0
3 years ago
Heather spent $138 on shirts. Fancy shirts cost $26 and plain shirts cost $15. If she bought a total of 7, then how many of each
Jlenok [28]
She bought about 3.5
3 0
4 years ago
Marsha Waite borrows $7,000 and agrees to pay it back in 2 years if the simple interest rate is 15%
I am Lyosha [343]

Answer:

Marsha must pay in 2 years \$9,100

Step-by-step explanation:

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A  is the amount of money to pay

P is amount of money borrowed  

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=2\ years\\ P=\$7,000\\ A=?\\r=15\%=15/100=0.15

substitute in the formula above

A=7,000(1+0.15*2)

A=7,000(1+0.30)

A=7,000(1.30)

A=\$9,100

therefore

Marsha must pay in 2 years \$9,100

3 0
3 years ago
In the expansion of (ax+1)^7<br> the fifth term is 945x^3<br> Find the value of a.
Advocard [28]

Answer:

a = 3

Step-by-step explanation:

First start writing out the binomial expansion of (ax + 1)^7

[1^7] + [7C1 * 1^6 *(ax)] + [7C2*1^5*(ax)^2]+[7C3*1^4*(ax)^3]

as you can see from this, the last bracket will produce our x^3 term

7C3*1^4*a^3x^3 \\35a^3x^3\\35a^3 = 945\\a^3 = 27\\a = 3

Hope this helps, let me know if you have any questions :)

6 0
3 years ago
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