The final answer would depend in the type of triangle we are analyzing, however here are the possible outcomes:
1.) If it was a right triangle, 36.5 would be the smaller angle.
2.) It cannot be an equilateral triangle since all angles would be 60°.
3.) In a isosceles triangle, 36.5° would be the smaller, since the others would be 72°.
4.) In an scalene triangle it cannot be determined unless we had 2 angles since in that kind of triangle all angles can be different.
5.) In an acute triangle, 36.5° would be the smaller angle.
6.) In an obtuse triangle it cannot be determined unless we had 2 angles, since it can have highly acute angles.
9514 1404 393
Answer:
perimeter ≈ 12.4 units
Step-by-step explanation:
The side adjacent to the angle is given. The relationships useful for the other two sides are ...
Tan = Opposite/Adjacent
Cos = Adjacent/Hypotenuse
From these, we have ...
opposite = 5·tan(22°) ≈ 2.02
hypotenuse = 5/cos(22°) ≈ 5.39
Then the perimeter is ...
P = a + b + c = 2.02 + 5 + 5.39 = 12.41
The perimeter of ∆ABC is about 12.4 units.
Answer:
The larger number is -6, the smaller number is -15
Step-by-step explanation:
We have two numbers, a and b.
We know that one number is larger than another by 9.
Then we can write:
a = b + 9
then a is larger than b by 9 units.
If the greater number is increased by 10 (a + 10) and the lesser number is tripled (3*b), the sum of the two would be -41:
(a + 10) + 3*b = -41
So we got two equations:
a = b + 9
(a + 10) + 3*b = -41
This is a system of equations.
One way to solve this is first isolate one variable in one of the two equations:
But we can see that the variable "a" is already isolated in the first equation, so we have:
a = b + 9
now we can replace that in the other equation:
(a + 10) + 3*b = -41
(b + 9) + 10 + 3*b = -41
now we can solve this for b.
9 + b + 10 + 3b = -41
(9 + 10) + (3b + b) = -41
19 + 4b = -41
4b = -41 -19 = -60
b = -60/4 = -15
b = -15
then:
a = b + 9
a = -15 + 9 = -6
a = -6
Answer:
Jacob served 16 quarts of juice.
Step-by-step explanation:
Hii!
So I did this and I have A!
A: You cannot get the mean from the graph but you CAN get the third quartile!
B: To find the interquartile range (IQR) we subtract the third and first quartiles:
60-35 = 25
C: An outlier would be much larger than the rest of the data or much smaller than the rest of the data. An outlier would make the "whisker" portion longer and could potentially slightly shift the box.
