Take the derivative with respect to t

the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero

divide by w

we add sin(wt) to both sides

divide both sides by cos(wt)

OR

(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

since 2npi is just the period of cos

substituting our second soultion we get

since 2npi is the period

so the maximum value =

minimum value =
Answer:
The height is 6 unit
The base is 2 units.
Step-by-step explanation:The given rectangle has vertices (–4, 7), (–2, 7), (–2, 1), and (–4, 1).
Answer:
n=0
Step-by-step explanation:
Clear parenthesis w/ distribution:
3(-7n+1)=-21n+3
Move everything over to one side:
6n+3=-21n+3
6n=21n Subtract the 3 on the right.
-15n=0 Subtract the 21.
n=0 Divide the -15.
The first one is 7.4 . 39/5=7 and 4 change so 7.4 . The second one is 1.67 . 5/3 is 1.6 repeated and rounded to the nearest houndredth is 1.67