Hello,
Since 3sin x-4sin^3x=sin (3x) (*****)
3sin x-4sin^3x=-1
==>sin (3x)=-1
==>3x=3π/2 +2kπ
==>x=π/2+2kπ/3, k being an integer
(*****)
sin (3x)=sin(x+2x)=sin x cos2x+cos x sin 2x
=sin x(cos²x-sin²x)+2cos²x sin x
=sin x(cos²x+2cos²x-sin²x)
=sinx(3(1-sin²x)-sin²x)
=3sin x-4sin^3x
Answer:
Step-by-step explanation:
A=(1,2,3)
B=(0,1,2)
A×B=(1,2,3)×(0,1,2)
A×B=((0,1),(1,1),(1,2),(0,2),(1,2),(2,2),(0,3),(1,3),(2,3))
Answer:
the first choice, the second choice, and the last choice
Step-by-step explanation:
5 and 6 because they are alternate angles
2 and 3 because they are corresponding angles
2 and 4 because they are corresponding angles
Answer:
10,404/334,084
Step-by-step explanation:
Given the polynomial
289r^2 - 102r + c
We are to find the value of c that will make it a perfect square
Divide through by 289
289r²/289 - 102r/289 + c/289
Half of the coefficient of r is 1/2(102/289)
Half of the coefficient of r = 102/578
Square the result
r² = (102/578)²
r² = 10,404/334,084
Hence the required constant is 10,404/334,084
I need more info to work with
