Question

Fluorine gas a 300 K occupies a volume of 500 mL. To what temperature should it be lowered to bring the volume to 300 mL?

Answer 1

180 K

V1/T1 = V2/T2
V1 = 500 mL
T1 = 300 K
V2 = 300 mL

Solve the equation for T2 —> T2 = V2T1/V1

T2 = (300 mL)(300 K) / (500 mL) = 180 K