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mojhsa [17]
3 years ago
14

A ___________ is a heterogeneous mixture in which the particles settle to the bottom.

Chemistry
1 answer:
uysha [10]3 years ago
3 0
<h2>suspension should be correct </h2>

<u>a suspension  </u>

<em>the particles are big enough to settle  </em>

<em> </em>

<u>a colloid</u>  

<em>the particles are too small to ever settle </em>

<u>a solution </u>

<em>homogeneous mixture of two or more substances</em>

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Kate wrote the steps of the carbon cycle to describe how carbon is cycled through specific organisms. The steps are in random or
Kobotan [32]
<h3>Answer:</h3>

3, 2, 1, 4

<h3>Further explanation:</h3>

The process of photosynthesis is the process of converting carbon dioxide and water into energy in the form of carbohydrates using sunlight. Usually done by plants that have leafy za called chlorophyll.

Carbohydrates themselves are formed from the C-carbon, H-hydrogen and O-oxygen components

Rabbit food is carrots that contain carbohydrates, which are part of the photosynthesis process

3. The carrot plant takes in carbon dioxide from the air during photosynthesis.

Reaction

6CO₂ + 6H₂O ⇒ C₆H₁₂O₆ + 6O₂

2. The rabbit eats the carrot plant.

Rabbits meet their carbohydrate source for energy by eating carrots

1. The rabbit decomposes.

Rabbits in time will experience a process of decomposition

4 - Carbon compounds are returned to the soil.

The carbon content in rabbits will also be decomposed into the soil again

3 0
3 years ago
Read 2 more answers
Osmium has a density of 22.6 g/cm^3. What volume (in cm^3) would be occupied by a 21.8 g sample of osmium?
Snowcat [4.5K]

0.9645 cm³ is the occupied volume by a 21.8 g sample of osmium of density of 22.6 g/cm^3.

Given values are:

  • Mass, m = 21.8 g
  • Density, d = 22.6 g

Density is given by,

  density = \frac{mass}{volume}

⇒volume = \frac{mass}{volume}

⇒volume = \frac{21.8}{22.6}

⇒volume = 0.9645 cm^3

∴The volume is 0.9645cm^3

To learn more about Density: brainly.com/question/15164682     #SPJ4

6 0
2 years ago
A student ran the following reaction in the laboratory at 311 K:CH4(g) + CCl4(g) 2CH2Cl2(g)When she introduced 4.10×10-2 moles o
statuscvo [17]

<u>Answer:</u> The value of K_{eq} is 0.044

<u>Explanation:</u>

We are given:

Initial moles of methane = 4.10\times 10^{-2}mol=0.0410moles

Initial moles of carbon tetrachloride = 6.51\times 10^{-2}mol=0.0651moles

Volume of the container = 1.00 L

Concentration of a substance is calculated by:

\text{Concentration}=\frac{\text{Number of moles}}{\text{Volume}}

So, concentration of methane = \frac{0.0410}{1.00}=0.0410M

Concentration of carbon tetrachloride = \frac{0.0651}{1.00}=0.0651M

The given chemical equation follows:

                    CH_4(g)+CCl_4(g)\rightleftharpoons 2CH_2Cl_2(g)

<u>Initial:</u>          0.0410    0.0651

<u>At eqllm:</u>     0.0410-x   0.0651-x       2x

We are given:

Equilibrium concentration of carbon tetrachloride = 6.02\times 10^{-2}M=0.0602M

Evaluating the value of 'x', we get:

\Rightarrow (0.0651-x)=0.0602\\\\\Rightarrow x=0.0049M

Now, equilibrium concentration of methane = 0.0410-x=[0.0410-0.0049]=0.0361M

Equilibrium concentration of CH_2Cl_2=2x=[2\times 0.0049]=0.0098M

The expression of K_{eq} for the above reaction follows:

K_{eq}=\frac{[CH_2Cl_2]^2}{[CH_4]\times [CCl_4]}

Putting values in above expression, we get:

K_{eq}=\frac{(0.0098)^2}{0.0361\times 0.0603}\\\\K_{eq}=0.044

Hence, the value of K_{eq} is 0.044

8 0
3 years ago
1. A rock with a mass of 66.5g<br>occupies 23.0 cm. Density?​
telo118 [61]

Answer:

2.89 g/cm^3

Explanation:

Since density equals mass over volume (or also seen as d=\frac{m}{v} ), simply divide 66.5 grams by 23.0 cm. This will output an answer of 2.89 g/cm^3.

7 0
3 years ago
Convert 2.17 x 10 -8 Mg into pg
viktelen [127]
This answer is 24 because 2.17 x 10 -8 is 24 so that would be your answer
4 0
3 years ago
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