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insens350 [35]
3 years ago
8

What is the mass of 6.02 x 1023 particles of rubidium carbonate

Chemistry
1 answer:
Firdavs [7]3 years ago
4 0

Answer:

Explanation:

84.97

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3 years ago
Please select the most appropriate answer for the blank: Entropy change is defined only along the path of a(n) ___________ proce
Whitepunk [10]

Entropy change is defined only along the path of an internally reversible process path.

<h3><u>What is Entropy Change </u>?</h3>
  • Entropy is a measure of a thermodynamic system's overall level of disorder or non-uniformity. The thermal energy that a system was unable to use to perform work is known as entropy.
  • Entropy Change is a phenomena that measures how disorder or randomness have changed inside a thermodynamic system.
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8 0
2 years ago
Explain, in terms of particles, what happens when methane boils and why
Ronch [10]

Answer:Butane > ethane > methane, because between bigger molecules there are stronger van der Waals forces and also higher molar mass means they need to be given more energy to have enough kinetic energy to move quickly, freely in gas.

There are multiple butene isomers (Butene) and some (2-Butenes - cis and trans) actually have higher boiling point than n-Butane (there is also Isobutane, of course, with quite much lower boiling point than all of them) and some (1-Butene, Isobutylene) have lower, so this isn't really a fair or simple question. But on simplest level, it can again be said that 1-butene has lower boiling point because it has very similar shape but slightly lower molar mass (2H less) than n-butane.

Explanation:

3 0
2 years ago
A 100g sample of Carbon-14 has a half-life of 5 years. How much Carbon-14 is left after 10 years?
attashe74 [19]

Answer: The amount of carbon-14 left after 10 years is 25 g

Explanation:

Formula used :

a=\frac{a_o}{2^n}

where,

a = amount of reactant left after n-half lives = ?

a_o = Initial amount of the reactant = 100 g

n = number of half lives =\frac{\text {given time}}{\text {half life}}=\frac{10}{5}=2

Putting values in above equation, we get:

a=\frac{100g}{2^2}

a=\frac{100g}{4}=25g

Therefore, the amount of carbon-14 left after 10 years is 25 g

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3 years ago
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