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monitta
3 years ago
14

Giving Brainliest to whoever answers well & first. 

Mathematics
2 answers:
Ne4ueva [31]3 years ago
7 0
Hopefully this helped :D

Blababa [14]3 years ago
4 0
∠C and ​ ∠D ​ are vertical angles with m∠C=−2x+90 and m∠D=x−30 .

m∠D = 10
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Factorise <img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="lat
Amanda [17]

Answer:

a1= 1   q= −sinx  , dla |q| <1   , ta suma jest zbieżna  

 a1   1  

S=  

=  

 1 −q   1+sinx  

w mianowniku podobnie:   a1=1  ,  q= sinx  , dla  | sinx| <1

 1  

S=  

 1 −sinx  

i mamy równanie:

 

1  

1+sinx  

 

 

= tg2x

 

1  

1− sinx  

 

Step-by-step explanation:

5 0
2 years ago
Which of the following shows the solution to m+5 &gt;-1
Ne4ueva [31]
The first one m > -6
6 0
3 years ago
Read 2 more answers
What is the area of the shaded region?
Mekhanik [1.2K]

9514 1404 393

Answer:

  434 -49π ≈ 280.1 cm²

Step-by-step explanation:

The shaded area is the difference between the enclosing rectangle area and the circle area.

The rectangle is 14 cm high and 31 cm wide, so has an area of ...

  A = WH

  A = (31 cm)(14 cm) = 434 cm²

The circle area is given by ...

  A = πr²

  A = π(7 cm)² = 49π cm²

__

The shaded area is the difference of these, so is ...

  shaded area = rectangle - circle

  = (434 - 49π) cm² ≈ 280.1 cm²

4 0
2 years ago
Elliot has a total of 26 books. He has 12 more fiction books than nonfiction books. Let x represent the number of fiction books
Llana [10]
X and y are books
x is fiction
y=nonifiction

x+y=36


x=12+y

12+y+y=26
2y+12=26
minus 12
2y=14
divide 2
y=7


sub
x=12+y
x=12+7
x=19

nonfiction=7
5 0
3 years ago
Determine whether the improper integral converges or diverges, and find the value of each that converges.
Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

u=x             dv=e^(2x)\cdot{dx}

du=dx         v=2\cdot{e^(2x)}

\int\limits^a_b {u} \, dv = uv -\int\limits^a_b {v} \, du

\int\limits^a_b {x\cdot{e^2^x} \, dx =2xe^2^x- \int\limits^a_b {2e^2^x} \, dx

\int\limits^a_b {xe^2^x} \, dx = 2xe^2^x-2e^2^x-C

We can therefore determine that if x tends to 0 the limit is -1

\lim_{x \to \0} 2xe^2^x-2e^2^x=0-1=-1

5 0
3 years ago
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