Answer:
position: (-6, -4)
range: 6
Step-by-step explanation:
The equation is that of a circle centered at (-6, -4) with a radius of √36 = 6. We presume that the "position" is that of the circle's center, and the "range" is the radius of the circle.
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The standard form equation of a circle with center (h, k) and radius r is ...
(x -h)^2 +(y -k)^2 = r^2
Matching parts of the equation, we find ...
h = -6, k = -4, r = √36 = 6.
7x+2
Step-by-step explanation:
add all the sides of the pentagon and make it equal to the perimeter of the square which is 4y
sides of the pentagon are
5x+3
2x+3
7x+4
9x-10
5x+8
28x+8=4y
7x+2 = y
7x+2 = answer
gathmath
gathmathier6961
another way :
in a standardized test you may want to use real numbers
make x equal a prime number like 3
so then the sides are
18
9
25
17
23
=
92
then divide by 4
23
then divide by 3
which is 7 remainder of 2
which is
7x+2
2/3 because you can divide the top and bottom by 8
Answer:
19
Step-by-step explanation:
PEMDAS
no parenthesis
no exponents
4-6+2 x 7
4-6+ 17
no division
4-6=2
2+17
19 is the answer
So I'll walk through the first 2. Then please try the other ones and let me know if you run into more problems.
5m-6
If m is equal to 7, then replace m with 7.
5(7)-6
5x7=35 so the expression is now 35-6. Solve.
35-6=29
So that was the first one.
4m+t
We just do what we do with the first problem.
4(7)+(2)
4x7=28 so the expression is 28+2.
28+2=28
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hope it helps
p.s. When there is subtraction, add. When there is division, multiply to cancel that out. When there is multiplication, divide to cancel. etc.
