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aleksandrvk [35]
3 years ago
11

The Dean of the Education department at a major college is awarded a $250,000 grant. He is allowed to pay himself out of that gr

ant, and can also use the money for his department's improvement. A study of how much he gives himself and how much he uses for other purposes would be studying the Dean's ________.
Mathematics
1 answer:
AlladinOne [14]3 years ago
4 0

Answer:

The answer is social value orientation.

Explanation:

Social value orientation is the preference or choice of a person about distributing and allocating resources such as money between himself and another person. It refers to the concern a person has for others and how much weight a person assigns to other people's well being in relation to his own . Social value orientation concept is studied in various scientific disciplines. Here the Dean's social value orientation studies how much he spends for himself and how much money he uses for the department's improvement from the awarded grant.

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Number 20 pls I need help with this one
Norma-Jean [14]
He uses 5/8 tanks of gas in one week.

In 5 he will use, 5/8 *5 = 25/8 in 5 weeks 
This can be simplified too:
3.125 tanks of gas

The answer is, 25/8 tanks of gas or 3.125 tanks of gas

3 0
3 years ago
Write a function rule for the relationship. the amount c of energy you burn and the time t you spend exercising, if you burn Cal
gregori [183]

Answer:

c= 12t

c is the amount of energy you burn, so it'll be the "solution" to the equation. Multiply 12 times the amount of time you spend exercising to find how much energy you'll burn.

6 0
3 years ago
Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.
Leya [2.2K]

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6

6 0
3 years ago
The following numerically ordered sequence of numbers has a mean of 17 and a median of 18.
lianna [129]
The values of a and b equals 10
4 0
2 years ago
Maureen earned some money doing odd jobs last summer and put it in a savings account that earns 9% interest compounded quarterly
ivolga24 [154]

Answer:

Maureen earned $123.19 doing odd jobs

Step-by-step explanation:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit year and t is the time in years for which the money is invested or borrowed.

In this question:

Compounded quarterly means that n = 4

10 years, so t = 10

9% interest, so r = 0.09

There is $300.00 in the account, which means that A = 300

How much did Maureen earn doing odd jobs?

This is P.

A(t) = P(1 + \frac{r}{n})^{nt}

300 = P(1 + \frac{0.09}{4})^{4*10}

(1.0225)^{40}P = 300

P = \frac{300}{(1.0225)^{40}}

P = 123.19

Maureen earned $123.19 doing odd jobs

5 0
3 years ago
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