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OlgaM077 [116]
3 years ago
12

In the given figure pt is the bisector of angle qpr. qs=3x, rs=2x+2, pq=3y-1 and pr=y+5

Mathematics
1 answer:
Naddika [18.5K]3 years ago
5 0

Answer:

See solutions below

Step-by-step explanation:

1) From the diagram QS = RS

3x = 2x+2

3x-2x = 2

x = 2

Since RS = 2x+2

RS = 2(2)+2

RS = 4 + 2

RS = 6

2) RQ = RS + QS

RQ = 2x+2 + 3x

RQ = 5x+2

RQ = 5(2)+2

RQ = 12

3) PQ = PR

3y-1 = y+5

3y-y = 5+1

2y = 6

y = 3

PQ = 3y-1

PQ = 3(3)-1

PQ = 8

4) PR = y+5

PR = 3+5

PR = 8

5) PQSR = PQ + QR

PQSR = 8 + 12

PQSR= 20

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Factor: 
3x^2 + 27
= 3(x^2  + 9)
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A) (3x + 9i)(x + 3i)
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= (3x)(x) + (3x)(3i) + (9i)(x) + (9i)(3i)
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B) (3x - 9i)(x + 3i)
= (3x +  - 9i)(x + 3i)
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C) (3x - 6i)(x + 21i)
= (3x +  - 6i)(x + 21i)
= (3x)(x) + (3x)(21i) + (- 6i)(x) + ( -6i)(21i)
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D) (3x - 9i)(x - 3i)
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= (3x)(x) + (3x)( - 3i) + (- 9)(x) + ( - 9)( - 3i)
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= 9ix + 3x^2 + 27i - 9x









Hope that helps!!!

8 0
4 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

Using the formula for finding the length of am arc

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Answer:

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