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OlgaM077 [116]
2 years ago
12

In the given figure pt is the bisector of angle qpr. qs=3x, rs=2x+2, pq=3y-1 and pr=y+5

Mathematics
1 answer:
Naddika [18.5K]2 years ago
5 0

Answer:

See solutions below

Step-by-step explanation:

1) From the diagram QS = RS

3x = 2x+2

3x-2x = 2

x = 2

Since RS = 2x+2

RS = 2(2)+2

RS = 4 + 2

RS = 6

2) RQ = RS + QS

RQ = 2x+2 + 3x

RQ = 5x+2

RQ = 5(2)+2

RQ = 12

3) PQ = PR

3y-1 = y+5

3y-y = 5+1

2y = 6

y = 3

PQ = 3y-1

PQ = 3(3)-1

PQ = 8

4) PR = y+5

PR = 3+5

PR = 8

5) PQSR = PQ + QR

PQSR = 8 + 12

PQSR= 20

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6 0
2 years ago
-2 -13.8x = -8 -(6x+1)
Varvara68 [4.7K]
-2 -13.8x = -8 -6x -1
First, I distributed the negative 1 that was outside of the parentheses to the positive 6x and the positive 1.

-2 -13.8x = -9 -6x
Then I added the negative 8 to the negative 1 which equals negative 9.

-2 -13.8x +6x = -9 -6x +6x
After that I used the addition property and added a positive 6x to both sides.

-2 -7.8x = -9
Then simplifying.

+2 -2 -7.8x = -9 +2
After simplifying, I used the addition property again, adding a positive 2 to both sides.

-7.8x = -7
Simplified.

-7.8x (-1) = -7 (-1)
Then I multiplied both sides by with a negative 1 since the variable cannot be a negative.

7.8x = 7
Simplified

(1/7.8) 7.8x = (1/7.8) 7
Then, to isolate the veriable, I multiplied 1/7.8 to both sides.

x = 1.11428571429
The answer !

I hope this helped !
7 0
3 years ago
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